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zmey [24]
3 years ago
9

Volume of a cuboid whose edges are 4 cm, 5 cm and 6 cm​

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Answer:

120 cm^3

Step-by-step explanation:

the edges are 4 cm 5 cm 6 cm

volume of cuboid=l×b×h

=4cm×5cm×6cm

=120cm^3

Mariana [72]3 years ago
8 0

Answer:

120

Step-by-step explanation:

Formula for cuboid: L × W × H

Plug in:

L × W × H

4 × 5  × 6

^    ^

20    ×  6

 ^          ^

     120

Hope this helps.

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Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
4 years ago
Lyle uses a streaming service to watch movies. Last month he paid $26.91 and watched 9 movies. If he watches 11 movies this mont
Anastasy [175]

Answer:

A. $32.89

Step-by-step explanation:

Take the amount and divide by the number of movies watched

26.91 / 9 =2.99

Now multiply by the new number of movies he wants to watch, 11

2,99 *11

32.89

5 0
1 year ago
Read 2 more answers
Calculate the force created from an object with a mass of 1250 grams and an acceleration of 3 m/s^2
abruzzese [7]

The force created by the object is 3.75 Newton.

Given

Mass of the object (m)  = 1250 grams

Convert 1250 grams to kilograms by dividing it by 1000.

Mass (m) = 1.25 kg

Acceleration of the body (a) = 3 m/s^{2}

From Newton's second law we know F= m *a

By Substituting in the above equation we get

Force = 1.25 x 3

Force = 3.75 kg/m /s^{2}

It can also be written as force = 3.75 N

Hence Force created by the body is 3.75 Newton.

To know more about Force refer

brainly.com/question/13191643?referrer=searchResults

8 0
1 year ago
40% of x is 35. What is the equation to find x
Dima020 [189]

Answer:

.40 x = 35  equation

x = 87.5

Step-by-step explanation:

Of means multiply and is means equals

40% * x = 35

Change percent to decimal form

.40 x = 35

Divide each side by .40

.40x/.40 = 35/.40

x = 35/.40

x =87.5

4 0
3 years ago
Read 2 more answers
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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