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zmey [24]
2 years ago
9

Volume of a cuboid whose edges are 4 cm, 5 cm and 6 cm​

Mathematics
2 answers:
Travka [436]2 years ago
8 0

Answer:

120 cm^3

Step-by-step explanation:

the edges are 4 cm 5 cm 6 cm

volume of cuboid=l×b×h

=4cm×5cm×6cm

=120cm^3

Mariana [72]2 years ago
8 0

Answer:

120

Step-by-step explanation:

Formula for cuboid: L × W × H

Plug in:

L × W × H

4 × 5  × 6

^    ^

20    ×  6

 ^          ^

     120

Hope this helps.

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Mr. Perez went to his favorite restaurant for lunch. his lunch cost $15.00. what was the total bill if yes left a 20% tip?
Mamont248 [21]
To find how much you paid for the tip, take the price of the meal and multiply by the tip rate (presented as a decimal)
so 15×.2 will equal what tip you pay
then just add that to the price of the meal
7 0
3 years ago
A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the
Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

=n-1\\=15-1\\=14

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145  

0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)  

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0
2 years ago
What is the perimeter of a parallelogram, if its area is 24 cm^2 and and the distances between the point of intersection of the
Stells [14]
Answer is 20 cm i guess

4 0
3 years ago
The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0
3 years ago
Which is not true <br><br> 10 + 9 = 7 + 12<br> 10 = 10<br> 10 - 4 = 3 + 3<br><br> 10 = 19 - 11
Natasha2012 [34]

Answer:

10=19-11

Step-by-step explanation:

that answer is false because 19-11 = 8 not 10

3 0
2 years ago
Read 2 more answers
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