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Volgvan
3 years ago
13

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112 A. Median: 102, Q1: 87, Q3: 113, IR: 28, outliers: none B. Median: 102, Q1: 87, Q3: 115, IR: 28, outliers: 68 C. Median: 102, Q1: 87, Q2: 115, IR: 28, outliers: none D. Median: 102, Q1: 87, Q3: 115, IR: 27, outliers: none
Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

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ololo11 [35]

Answer:

x = -5, and y = -6

Step-by-step explanation:

Suppose that we have two equations:

A = B

and

C = D

combining the equations means that we will do:

First we multiply both whole equations by constants:

k*(A = B) ---> k*A = k*B

j*(C = D) ----> j*C = j*D

And then we "add" them:

k*A + j*C = k*B + j*D

Now we have the equations:

-x  - y = 11

4*x - 5*y = 10

We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.

Then we can take the first equation:

-x  - y = 11

and multiply both sides by 4.

4*(-x - y = 11)

Then we get:

4*(-x - y) = 4*11

-4*x - 4*y = 44

Now we have the two equations:

-4*x - 4*y = 44

4*x - 5*y = 10

(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)

If we add them, we get:

(-4*x - 4*y) + (4*x - 5*y) = 10 + 44

-4*x - 4*y + 4*x - 5*y = 54

-9*y = 54

So we combined the equations and now ended with an equation that is really easy to solve for y.

y = 54/-9 = -6

Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.

-x - y = 11

-x - (-6) = 11

-x + 6 = 11

-x = 11 -6 = 5

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Then:

x = -5, and y = -6

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3 years ago
In a swimming competition, Grace jumped from the height of 22 meters. The following table represents the height f (t), in meters
exis [7]

For this case we have the following variables:

t: time in seconds.

f (t): height as a function of time.

By the time Grace reaches the pool, the height is equal to zero.

We have the following table:

Time (t) (in seconds) Height f(t) (in meters)

          1                                   25

          2                                  20

          3                                   15

          4                                   0

We observe that the height is equal to zero after 4 seconds.

Equivalently:

f (4) = 0

Answer:

the following represents the x-intercept of f(t):

Grace reaches the swimming pool after 4 seconds

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3 years ago
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