Inequalities help us to compare two unequal expressions. (-6, 3) is not the solution to the system of inequalities.
<h3>What are inequalities?</h3>
Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.
The graph of y ≥ −3x + 3 will be a solid line with the equation y=−3x + 3, this solid line signifies that the value on this line is also included in the solution. Since the symbol is '≥' therefore the area above the line will have the solutions.
The graph of y<(3/2)x -6 will be a dashed line with the equation y=(3/2)x - 6, this dashed line signifies that there is no solution on the line. since the inequality symbol is '<' therefore, the area under the dashed line will have all the solutions.
The area where both shaded areas meet is the area that will have all the possible solutions.
PartB:
y ≥ −3x + 3
3 ≥ -3(-6) + 3
3 ≥ 18 + 3
Since the above inequality is not satisfied, (-6, 3) is not the solution to the system of inequalities.
Learn more about Inequality:
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Answer: f(x) = -9x
Step-by-step explanation:
Remember that f(x) is the same thing as y.
y = 3x + 6x + 2y
First, combine like terms to get...
y = 9x + 2y
Then, subtract -2y from each side to get..
-y = 9x
Next, you divide by -1 and get...
y = -9x ,which is your answer
Hope this is helpful :)
S’ would be located in (-9,-3)
Answer: Daughter = 13, Man = 45
<u>Step-by-step explanation:</u>
<u>Today</u> <u>5 yrs ago</u> <u>3 years hence (future)</u>
Man x x - 5 x + 3
Daughter y y - 5 y + 3
5 years ago a man's age was 5 times the age of his daughter's
EQ1: x - 5 = 5(y - 5) → x - 5 = 5y - 25 → x - 5y = -20
3 years hence, twice the man's age will be equal to 6 times his daughter's age.
EQ2: 2(x + 3) = 6(y + 3) → 2x + 6 = 6y + 18 → 2x - 6y = 12
Solve the system of equations using the Elimination method:
EQ1: x - 5y = -20 → -2(x - 5y = -20) → -2x + 10y = 40
EQ2: 2x - 6y = 12 → 1(2x - 6y = 12) → <u> 2x - 6y</u> = <u> 12 </u>
4y = 52
<u> ÷4 </u> <u> ÷4 </u>
y = 13
Substitute y = 13 into either equation to solve for x:
EQ1: x - 5y = -20
x = 5y - 20
x = 5(13) - 20
x = 65 - 20
x = 45
