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olga2289 [7]
3 years ago
13

Write an equation for the line in slope-intercept form.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
5 0
Y=3x+4
it’s hard to tell where the line is meeting the corners of the small squares but slope intercept is y=mx+b
m is slope
b is y intercept
it appears as the line intercepts the y axis at 4 so that is your y intercept. the slope is 3/1 which is just 3 so you would end up with y=3x+4
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Which function is equivalent to h(x)=10x2+9x-1?
jolli1 [7]

Answer:

i think the answer is c

Step-by-step explanation:

4 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4



draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
Solve:
Misha Larkins [42]

Answer:

convert 3 1/3 to an improper fraction

3*3 = 9

9+1 = 10

10/3

multiply the numerator by 4

(10/3) * 4 = 40/3

40/3 = 13 1/3

5 0
3 years ago
Read 2 more answers
what is an equation of the line that is parallel to the line with y=-.60x+2 and passes through the point (10,-10)
sp2606 [1]

y = -0.60x - 4

because the slope stays the same because it is parallel and the y intercept for the new equation ends up being -4

4 0
3 years ago
Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS: A) cos E = 312 + 392 – 2(3
defon

This question is incomplete because the options were not properly written.

Complete Question

Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS:

A) cos E = 31²+ 39² – 2(31)(39)

C) 56² = 39² – 2(39) ⋅ cos E

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Answer:

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Step-by-step explanation:

From the above diagram, we see are told to apply the law of cosines to solve for m∠E i.e Angle E

The formula for the Law of Cosines is given as:

c² = a² + b² − 2ab cos(C)

Because we have sides d , e and f and we are the look for m∠E the law of cosines would be:

e² = d² + f² - 2df cos (E)

e = 56

d = 39

f = 31

56² = 39² + 31² - (2 × 39 × 31) × cos E

Therefore, from the above calculation and step by step calculation, the option that applies the law of cosines correctly and could be solved to find m∠E

Is option D: 56² = 31² + 39² – 2(31)(39) ⋅ cos E

8 0
4 years ago
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