Answer:
3r^3/y^7.
Step-by-step explanation:
9y^-5 / 3y^2r^-3
9 / 3 = 3
y ^-5 / y^2 = y^-7 = 1 / 7y
1 / r^-3 = r^3
So the answer is 3r^3/y^7.
Answer: 306 inches or 25.5 feet or 8.5 yards.
Step-by-step explanation:
Given: Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of ribbon.
1 feet = 12 inches
length of ribbon Tino has = 12 x 7.5 = 90 inches
1 yard = 36 inches
length of ribbon Baxter has = 3.5 x 36 = 126 inches
Total ribbon they have = (length of ribbon Carol has) + (length of ribbon Tino has) + (length of ribbon Baxter has)
= (90+90+126) inches
= 306 inches
In feet , Total ribbon =
![[\text{ 1 inch}=\dfrac{1}{12}\text{ feet}]](https://tex.z-dn.net/?f=%5B%5Ctext%7B%201%20inch%7D%3D%5Cdfrac%7B1%7D%7B12%7D%5Ctext%7B%20feet%7D%5D)

In yards, Total ribbon =
![[\text{1 feet}=\dfrac{1}{3}\text{ yard}]](https://tex.z-dn.net/?f=%5B%5Ctext%7B1%20feet%7D%3D%5Cdfrac%7B1%7D%7B3%7D%5Ctext%7B%20yard%7D%5D)

Hence, the total length of ribbon the three friends have is 306 inches or 25.5 feet or 8.5 yards.
With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
Answer:
Step-by-step explanation:
Answer:
17 1/2
Step-by-step explanation:
19+7÷2-5
Solve using PEMDAS
Divide first
19 + 7/2 -5
Then add and subtract from left to right
Getting a common denominator
38/2 + 7/2 - 10/2
45/2 - 10/2
35/2
17 1/2