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2 years ago

PLEASE HELP ME ; w ;

Mathematics

2 answers:

jek_recluse [69]2 years ago

5 0

thx x]

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Rus_ich [418]2 years ago

3 0

Answer:

Thank u so much. So it was a few day before christmas and i decided to get my brother a persent. So when i got home i got duck tape wraping paper and that paper stuffing for like the christmas bags. Ok so anyway i wraped it taped it with duck tape then raped it in stuffing paper and. ducktaped that too. Then i wraped it agine and ducktaped it and then raped it in stuffing paper and taped it with duck tape. I did this about 5-7 times lol. The reaction of my brother was funny. It was a medium sized box with a small pack of gum. Like i couldnt stop laughing. If u want a good laugh try this or u can do it different if u want. Have a merry christmas :D

Step-by-step explanation:

p.s this was last year

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Y is directly related to X , and Y is 81 when X is 27.<br><br> The constant of variation is

zhenek [66]

Since x and y are directly related, the equation for their comparison will look like

kx = y

where k is your constant. They give you an instance in the problem where x = 27 and y = 81. Plug this into the above equation and solve for k.

kx = y
k (27) = 81
k = 3

Thus, the constant of variation is 3.

5 0

3 years ago

Read 2 more answers

In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally up and to the right. ho

valentina_108 [34]

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

$\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }$

<h2>Permutation ( Arrangement )</h2>

Permutation is the number of ways to arrange objects.

$\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }$

<h2>Combination ( Selection )</h2>

Combination is the number of ways to select objects.

$\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }$

Let us tackle the problem.

This problem is similar to Pascal Triangle.

The Lord can move to the right or up in one way only.

We can put "1" in each box on the bottom and left to represent 1 possible movement.

To get the possibility of movement to another box, we will add the possibility of movement to the left, right, and diagonal squares as shown in Figure 1.

This process is repeated for the next box as shown in Figure 2.

Finally, after this process is repeated until the top right box, we get the results as shown in Figure 3.

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard.

<h3>Learn more</h3>