Answer:
In the case of Mike's free throws, the Domain that describes this relationship can be either B or D.
Step-by-step explanation:
In the case of a relationship that represents a 'constant' increase or decrease, we know that there will be an independent and dependent variable. The independent variable is our 'x' value and the dependent variable is our 'y' value. In this case, they tell us that the number of free throws Mike misses is dependent on the number of practices sessions he has attended. Therefor, 'x' would represent the number of practices and 'y' would represent the number of missed free throws. At the start, before practices or an 'x' value of 0, Mike, misses 6 free throws. He continues to decrease his missed throws by for each practice, until the sixth practice where he misses none. So, the 'x' values would be 0, 1, 2, 3, 4, 5, and 6. This can be shown by letter 'B', which includes all numbers, or letter 'D', which represents all numbers between, and including 0 and 6.
12222x333=4069926 is the answer
A and D are correct. To understand this, you need to know that this scenario gives us a total (2 1/2 cups) and a part (1/4). When you have these 2 pieces of information you have either a division problem with a total divided into parts (choice D) or you have one part and a totol shown as a multiplication problem (choice A).
Answer:
You are a lazy Bum!!!!!
Step-by-step explanation:
You are a lazy Bum!!!!!You are a lazy Bum!!!!!
Answer:
25
Step-by-step explanation:
Given that:
A large circle in the park has its middle part painted.
The circle is divided in 4 equal parts.
Radius of the circle = 10 meters
To find:
Area of each section of the circle,
= ?
Solution:
Here, we need to find the area of the bigger circle first and then need to divide it into 4 equal parts to find out the answer.
First of all, let us have a look at the formula for area of a circle with given radius
:

Here, 
Putting the value in the above formula, we get:
So, area = 
Now, there are 4 equal parts of the circle, therefore area of each section will be equal.
Area of each section of the circle:
