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Illusion [34]
2 years ago
15

What is the value of the expression shown? 2 7 ÷ 3 7

Mathematics
2 answers:
Goshia [24]2 years ago
4 0

Answer:

The answer is 1.5 as a decimal or 3/2 as a fraction.

Step-by-step explanation:

You actually do 3/7 ÷ 2/7.

Novosadov [1.4K]2 years ago
3 0

Answer:

2/3

Step-by-step explanation:

2/7 ÷ 3/7

2/7 x 7/3

Cross simplify and you'll get 2/3

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Which of the following numbers is closer to the area of a circle with a radius of 2.1
Pachacha [2.7K]
B. 11.33 is closer to the area of a circle with a radius of 2.1
5 0
3 years ago
Read 2 more answers
The area of Caitlins square garden is 345 ft.². One side of the garden is next to a shed. She wants to put a fence around the ot
NikAS [45]

Hey there!!

The formula for the area of a square -  s²

where s = side

s² = 345

s = √345

s = 18.57 ft

Fence shall be three sides

So 18.57 × 3

The required answer = 55.71 ft

Hope my answer helps!

3 0
3 years ago
PLEASE HELP ME IN GEOMETRY!!!
puteri [66]

Answer:

7.20

Step-by-step explanation:

triangle is right triangle so other leg of first is 12

5 x 3/5 = 5, so

do 12 x 3/5 to get 7.20

7 0
2 years ago
Write the phrase as an expression. Then evaluate when x=5. The sum of a number x and 4, all divided by 3
frozen [14]
Sum of a number, x and 4 all divided by 3

sum of x and 4 means x+4
all divided by 3
\frac{x+4}{3}
evaluate for x=5

\frac{5+4}{3}=
\frac{9}{3}=
3

it's 3
3 0
3 years ago
Read 2 more answers
Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
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