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vova2212 [387]
2 years ago
14

a tub shaped like a cylinder with a diameter of 18 inches, And a height of 20 inches Is filled to the top with water. Six spheri

cal balls each with a diameter of 8 inches Are placed in the tub and they sink. some water overflows the tub, this amount equals a combined volume of the spheres. Find the exact and the approximate of water that remains in the tub.
Mathematics
1 answer:
jasenka [17]2 years ago
4 0

The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.

<h3>What is the approximate amount of water that remains in the tub?</h3>

The first step is to determine the volume of the cylinder.

Volume of the tub = πr²h

Where:

  • r = radius = diameter / 2 = 18/2 = 9 inches
  • h = height
  • π = 3.14

3.14 x 9² x 20 = 5086.8 in³

The second step is to determine the volume of the 6 balls.

Volume of a sphere= 4/3πr³

r = diameter / 2 = 8/2 = 4 inches

6 x (3.14 x 4/3 x 4³) = 1607.68 in³

Volume that remains in the tub = 5086.8 in³  -  1607.68 in³ = 3479.12 in³

To learn more about the volume of a sphere, please check: brainly.com/question/13705125

#SPJ1

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1.2(2.5)x - 1

Step-by-step explanation:

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3 years ago
Solve for base. 450 crates is 0.90% of ___ crates
Tema [17]
Well... if 450 is 90% of the crates then 500 is 100%. 450 crates is 0.90% of 500 crates.
8 0
3 years ago
Please help I really don’t know what to do
just olya [345]

Answer:

The answer is 0

Step-by-step explanation:

2 * 2 * 2 = 8

8 * 0.5 = 4

4 - 4 = 0

0 / 2 = 0

Make sure the 0.5 is actually 0.5, because it is hard to tell in that expression. if anything, anything, the steps are the same and all you would need to do is the change the numbers.

Hope this helps :)

7 0
3 years ago
A group of pennies made in 2018 are weighed. The mean is approximately 2.5 grams
Hatshy [7]

Answer:

*  The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.

* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.

Step-by-step explanation:

Recall that a penny is a money unit. It is created/produced, just like any other commodity. As a matter of fact, almost all types of money or currency are manufactured; with different materials ranging from paper to solid metals.

A group of pennies made in a certain year are weighed. The variable of interest here is weight of a penny.

The mean weight of all selected pennies is approximately 2.5grams.

The standard deviation of this mean value is 0.02grams.

In this context,

*  The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.

* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.

Likewise, adding 0.02g to the mean, you get the highest penny weight in the group.

Hence, the weight of each penny in this study, falls within

[2.48grams - 2.52grams]

4 0
3 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
3 0
4 years ago
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