How do I expand the brackets for the equation 5x(6x+1)?

A parabola opening up or down has vertex (0,0) and passes through (12, -18). Write its

denis-greek [22]

The equation is y= -1/8x^2

4 0

3 years ago

What is the value of ( 0.4) ^3

cestrela7 [59]

Answer:

0.064

Step-by-step explanation:

( 0.4) ^3

Solution :

( 0.4) ^3

= 0.4 x 0.4 x 0.4

= 0.064

8 0

3 years ago

(PLEASE HELP ME)(I WILL GIVE YOU BRAINLINEST)Suppose homes in a big city increase in value 13% every year. How much will a home

kolbaska11 [484]

Answer:

$216435

Step-by-step explanation:

Given : Suppose homes in a big city increase in value 13% every year.

To Find: How much will a home that cost $150,000 be worth 3 years later?

Solution:

Principal = $150000

Rate = 13% =0.13

Time = 3 years

Formula : $A=P(1+r)^t$

Now substitute the values in the formula

$A=150000(1+0.13)^3$

$A=216434.55$

So, The cost of home after 3 years will be $216435

Hence Option B is true

3 0

3 years ago

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago

When x=16 the value of y is 28. write an equation for y in terms of x

Burka [1]

Answer:

ig if it is brainiest

Step-by-step explanation:

y=1.75

4 0

3 years ago