Ask question

Ask question

All categories

3 years ago

10

Determine whether the given relation is an implicit solution to the given differential equation. assume that y is a function of

x.

1 answer:

Xelga [282]3 years ago

6 0

Differentiate:x^2 + y^2 = 4
You get this:2x + 2yy' = 0
bring the x variable on the other side:2yy' = -2x
Now divide 2y to leave y' by itself:y' = -2x/2y
Answer: y' = -x/y
The given relation is not a implicit solution to the given differential equation.

You might be interested in

Im not good with least to greatest in fractions, Please help me

tiny-mole [99]

Answer:

From least to greatest it is -5/2, -2, then 1.7

Step-by-step explanation:

First by process of elimination, 1.7 is the only positive number, so it is the greatest number compared to the other two.

Now we are left with -2 and -5/2.

We can rewrite -2 as $-\frac{2}{1}$ , as any number by itself itself is the number over 1.

Then we need to find the common denominator for both fractions, meaning they must share the same bottom number.

The 1 in the denominator can be multiplied by 2 to get a denominator of 2 , the same as the denominator for $-\frac{5}{2}$ .

Since the denominator is multiplied by 2, the numerator also has to be multiplied by 2:

$-\frac{2}{1} *\frac{2}{2}$ $=-\frac{4}{2}$

Now since both fractions share the same denominator, we can compare them by their numerators. 5 is greater than 4, but we must keep in mind that these are negative. The larger the negative number, the smaller the value.

So when comparing -4/2 and -5/2, -5/2 is smaller.

So our final answer from least to greatest is -5/2, -2, then 1.7

8 0

4 years ago

If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.

zmey [24]

Answer:

$a=3$ and $b=5$ .

Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

$2(4x+3)=a(x+7)+b(x-3)$

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

$2(4\cdot -7+3)=a(-7+7)+b(-7-3)$

$2(-28+3)=a(0)+b(-10)$

$2(-25)=0-10b$

$-50=-10b$

Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

$2(4\cdot 3+3)=a(3+7)+b(3-3)$

$2(12+3)=a(10)+b(0)$

$2(15)=10a+0$

$30=10a$

Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

4 0

3 years ago

Read 2 more answers

NEED THE ANSWER PLEASE

Alexus [3.1K]

Answer:

d. 89°

Step-by-step explanation:

The given measure of the angles formed are;

m∠AED = 48°, m $\widehat{AG}$ = 175°

According to circle theorem, the angle formed by a chord and a tangent of a circle is given by half of the measure of the arc intercepted by the chord in the direction of the angle;

Therefore;

m∠AED = (1/2) × m $\widehat{ABE}$ = 48°

∴ m $\widehat{ABE}$ = 2 × 48° = 96°

m∠AEF = (1/2) × m $\widehat{AGE}$

m $\widehat{ABE}$ + m $\widehat{AGE}$ = 360° (angle round a circle)

∴ m $\widehat{AGE}$ = 360° - m $\widehat{ABE}$ = 360° - 96° = 264°

m $\widehat{AGE}$ = m $\widehat{AG}$ + m $\widehat{EG}$

∴ m $\widehat{EG}$ = m $\widehat{AGE}$ - m $\widehat{AG}$ = 264° - 175° = 89°

m $\widehat{EG}$ = 89°.

5 0

3 years ago

I don’t understand how to do this at all.

avanturin [10]

Answer:

2m

Step-by-step explanation:

(m+3) (m-1)

We need to FOIL

first m*m = m^2

outer -1*m = -m

inner = 3m

last 3*-1 = -3

Add these together

m^2 -m +3m -3

m^2 +2m -3

3 0

4 years ago

The formula s= SA/6 squared gives the length of the side, s, of a cube with a surface area, SA. How much longer is the side of a

stiv31 [10]

The surface area (SA) of a cube can be written as:

SA = 6s²

From here we can write, the length of the side s as:

$s= \sqrt{ \frac{SA}{6} }$

For cube with surface area of 1200 square inches, the side length will be:

$s= \sqrt{ \frac{1200}{6} }=10 \sqrt{2}$ inches

For cube with surface area 768 square inches, the side length will be:

$s= \sqrt{ \frac{768}{6} }=8 \sqrt{2}$ inches

The difference in side lengths of two cubes will be:

$10 \sqrt{2} -8 \sqrt{2}=2 \sqrt{2}$

Rounding to nearest tenth of an integer, the difference between the side lengths of two cubes will be 2.8 inches.

7 0

3 years ago

Read 2 more answers