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V125BC [204]
3 years ago
6

Find the area VALUE of each figure below with the following measurements

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

the answer is 180cm for the rectangle

the answer is 126cm for the triangle.

the answer is 880ml for the rectangle.

Step-by-step explanation:

first diagram (rectangle)

area=l×b

15×12

180cm

second diagram(triangle)

area =

\frac{1}{2}  \times l \times b \\  \frac{1}{2}  \times 14 \times 18 \\  = 7 \times 18 \\ 126cm

third diagram( rectangle)

area=

l \times b \\  \\ 44 \times 20 \\ 880ml

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Mice21 [21]

Answer:

The answer is C

Step-by-step explanation

3 0
3 years ago
Find the sum of the convergent series 7 0.7 0.007
mafiozo [28]
7+0.7+0.007+\cdots=7\left(1+\dfrac1{10}+\dfrac1{100}+\cdots\right)

Let S_n denote the nth partial sum of the series, i.e.

S_n=1+\dfrac1{10}+\dfrac1{100}+\cdots+\dfrac1{100^n}

Then

\dfrac1{10}S_n=\dfrac1{10}+\dfrac1{100}+\dfrac1{1000}+\dfrac1{10^{n+1}}

and subtracting from S_n we get

S_n-\dfrac1{10}S_n=\dfrac9{10}S_n=1-\dfrac1{10^{n+1}}
\implies S_n=\dfrac{10}9\left(1-\dfrac1{10^{n+1}}\right)

As n\to\infty, the exponential term vanishes, leaving us with

\displaystyle\lim_{n\to\infty}S_n=\dfrac{10}9

and so

7+0.7+0.007+\cdots=7.777\ldots=\dfrac{70}9
3 0
3 years ago
The speed(S) of a car varies partly directly as its mass(M) and partly directly as the quantity (Q) of fuel in it. When the spee
weeeeeb [17]

Answer:

S varies partly directly as M and Q.

S=C.

S=KMQ+C.

For the first one...

speed=80,m=220,Q=30.

80=K20×30+C.

80=600K+C......(I).equation one.

For the second one....

speed=60,m=300,Q=40.

60=K300×40+C.

60=12000K+C.....(ii). equation two.

Minus eqtn(I) from eqtn(ii).

80=600K+C.

- 60=12000K+C.

K=0.01754~0.018.

Substitute K=0.018 into eqtn(I).

80=600K+C

80=600×0.018+C.

80=10.8+C.

C=80-10.8=69.2.

The relation is S=0.018MQ+69.2

when speed is 100 and mass is 250 find the volume.

100=0.018×250×Q+69.2.

100=4.5Q+69.2.

4.5Q=100-69.2

4.5Q=30.8.

Q=30.8/4.5.

Q=6.8~7litres.

6 0
3 years ago
Ann's first option is a plot of land adjacent to a current park.
oksian1 [2.3K]

Given:

The equation for the area of the first option is:

x^2+200x=166400

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

x^2+200x=166400

It can be written as:

x^2+200x-166400=0

Splitting the middle term, we get

x^2+520x-320x-166400=0

x(x+520)-320(x+520)=0

(x-320)(x+520)=0

x=320,-520

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0
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ch4aika [34]
Let the distance to his office be x, then
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7/30 = x/(3x + 15)
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30x - 21x = 105
9x = 105
x = 105/9 = 11.7 miles

Therfore he travels an average of 11.7 miles to work.
7 0
3 years ago
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