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3 years ago

Find the area VALUE of each figure below with the following measurements

Mathematics

1 answer:

Dmitry [639]3 years ago

3 0

Answer:

the answer is 180cm for the rectangle

the answer is 126cm for the triangle.

the answer is 880ml for the rectangle.

Step-by-step explanation:

first diagram (rectangle)

area=l×b

15×12

180cm

second diagram(triangle)

area =

$\frac{1}{2} \times l \times b \\ \frac{1}{2} \times 14 \times 18 \\ = 7 \times 18 \\ 126cm$

third diagram( rectangle)

area=

$l \times b \\ \\ 44 \times 20 \\ 880ml$

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Suppose the x-intercept of f(x) is (p,0) and the x-intercept of g(x) is (q,0). What is the value of p+q?

Mice21 [21]

Answer:

The answer is C

Step-by-step explanation

3 0

3 years ago

Find the sum of the convergent series 7 0.7 0.007

mafiozo [28]

$7+0.7+0.007+\cdots=7\left(1+\dfrac1{10}+\dfrac1{100}+\cdots\right)$

Let $S_n$ denote the $n$ th partial sum of the series, i.e.

$S_n=1+\dfrac1{10}+\dfrac1{100}+\cdots+\dfrac1{100^n}$

Then

$\dfrac1{10}S_n=\dfrac1{10}+\dfrac1{100}+\dfrac1{1000}+\dfrac1{10^{n+1}}$

and subtracting from $S_n$ we get

$S_n-\dfrac1{10}S_n=\dfrac9{10}S_n=1-\dfrac1{10^{n+1}}$
$\implies S_n=\dfrac{10}9\left(1-\dfrac1{10^{n+1}}\right)$

As $n\to\infty$ , the exponential term vanishes, leaving us with

$\displaystyle\lim_{n\to\infty}S_n=\dfrac{10}9$

and so

$7+0.7+0.007+\cdots=7.777\ldots=\dfrac{70}9$

3 0

3 years ago

The speed(S) of a car varies partly directly as its mass(M) and partly directly as the quantity (Q) of fuel in it. When the spee

weeeeeb [17]

Answer:

S varies partly directly as M and Q.

S=C.

S=KMQ+C.

For the first one...

speed=80,m=220,Q=30.

80=K20×30+C.

80=600K+C......(I).equation one.

For the second one....

speed=60,m=300,Q=40.

60=K300×40+C.

60=12000K+C.....(ii). equation two.

Minus eqtn(I) from eqtn(ii).

80=600K+C.

- 60=12000K+C.

K=0.01754~0.018.

Substitute K=0.018 into eqtn(I).

80=600K+C

80=600×0.018+C.

80=10.8+C.

C=80-10.8=69.2.

The relation is S=0.018MQ+69.2

when speed is 100 and mass is 250 find the volume.

100=0.018×250×Q+69.2.

100=4.5Q+69.2.

4.5Q=100-69.2

4.5Q=30.8.

Q=30.8/4.5.

Q=6.8~7litres.

6 0

3 years ago

Ann's first option is a plot of land adjacent to a current park.

oksian1 [2.3K]

Given:

The equation for the area of the first option is:

$x^2+200x=166400$

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

$x^2+200x=166400$

It can be written as:

$x^2+200x-166400=0$

Splitting the middle term, we get

$x^2+520x-320x-166400=0$

$x(x+520)-320(x+520)=0$

$(x-320)(x+520)=0$

$x=320,-520$

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0

3 years ago

on monday, roger drove to work in 20 minutes. on tuesday, he averaged 15 miles per hour more, and it took him 6 minutes less to

ch4aika [34]

Let the distance to his office be x, then
On monday, speed = x/20 miles per minutes = 3x miles per hour
On tuesday, speed = (3x + 15) miles per hour
Time = distance / speed
(20 - 6)/60 hours = x/(3x + 15) hours
7/30 = x/(3x + 15)
7(3x + 15) = 30x
21x + 105 = 30x
30x - 21x = 105
9x = 105
x = 105/9 = 11.7 miles

Therfore he travels an average of 11.7 miles to work.

7 0

3 years ago