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V125BC [204]
3 years ago
6

Find the area VALUE of each figure below with the following measurements

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

the answer is 180cm for the rectangle

the answer is 126cm for the triangle.

the answer is 880ml for the rectangle.

Step-by-step explanation:

first diagram (rectangle)

area=l×b

15×12

180cm

second diagram(triangle)

area =

\frac{1}{2}  \times l \times b \\  \frac{1}{2}  \times 14 \times 18 \\  = 7 \times 18 \\ 126cm

third diagram( rectangle)

area=

l \times b \\  \\ 44 \times 20 \\ 880ml

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4. A company manufactures tires to meet the annual demand of 125,000 production runs. One production run involves producing 100
lyudmila [28]

Answer:

a) Economic order or production quantity = 2,500 tires.

Number of production runs in a year = 50 runs

Hence, 2,500 tires should be produced in each of the 50 runs in a year to minimize total cost.

b) Minimum total inventory cost = Tsh 30,000

Step-by-step explanation:

The total cost for the tire production firm will be a sum of the total production cost and total inventory cost.

Total cost = Total Production cost + Total inventory cost

Total Production Cost = (Number of production runs in a year) × (Setup Cost of one production run)

Number of production runs in a year = (Annual demand)/(Number of units produced per production run)

Let the annual demand = D

Number of units produced per production run = Q

Setup Cost of one production run = S

Number of production runs in a year = (D/Q)

Total Production Cost = (DS/Q)

Total inventory Cost = (Average inventory level) × (Cost of holding 1 unit in inventory)

Average inventory level is usually assumed to be half of the number of units in a production run = (Q/2)

Cost of Holding a unit of product in inventory = H

Total inventory Cost = (QH/2)

Total cost = TC = (DS/Q) + (QH/2)

At minimum cost, (dTC/dQ) = 0

(dTC/dQ) = -(DS/Q²) + (H/2) = 0

(DS/Q²) = (H/2)

Q² = (2DS/H)

Hence,

Economic order/production quantity = Q = √(2DS/H)

For this question

D = Annual demand = 125,000 tires

S = Setup cost for one production run = Tsh 600

H = Holding cost for one unit in inventory = Tsh 24

Q = √(2×125000×600/24) = 2,500 units

Number of production runs in a year = (D/Q) = (125000/2500) = 50 production runs.

b) Total Inventory Cost = (QH/2)

At minimum total inventory cost, Q = 2,500

Minimum total inventory cost = (2500×24/2) = Tsh 30,000

Hope this Helps!!!

4 0
3 years ago
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