Idk what it’s asking for since u don’t show that but if it’s radius: 5. 18m, 6. 11.3 in, 7. 21 yd, if it’s diameter: 5. 36m, 6. 22.6in, 7. 42yd
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
Step-by-step explanation:
Answer:
a. [L], [M]
b. 41, 42, 43
Step-by-step explanation:
<h3>a.</h3>
If x represents the smallest number, then the second number is (x+1) and the third number is (x+2). The sum is of the first number (x), 3 times the second number, 3(x+1), and 2 times the third number, 2(x+2). That sum can be written as ...
Total = x +3(x +1) +2(x +2) . . . . matches [L]
If we use the distributive property to eliminate parentheses, we get ...
Total = x +3x +3 +2x +4 . . . . . matches [M]
__
<h3>b.</h3>
Using the equation of [M], we have ...
253 = x +3x +3 +2x +4
246 = 6x . . . . . . . . . . . . . . . . collect terms, subtract 7 from both sides
41 = x . . . . . . . . . divide both sides by 6
The three consecutive numbers are 41, 42, 43.
Answer: The required markup percentage is 60%.
Step-by-step explanation: Given that the store bought a pair of shoes for $50 and sold it for $80.
We are to find the markup percentage.
The markup price of the pair of shoes is given by
Therefore, the markup percentage is given by
Sorry if i was wrong. But this soulution makes since so i think im right! Also please brainlest!