X = measure of angle 1
y = measure of angle 2
z = measure of angle 3
w = measure of angle 4
Focus on the bottom triangle. The three angles add to 180 degrees
(angle 2) + (angle 3) + 116 = 180
y+z+116 = 180
y+z= 180-116
y+z= 64
Since we have the bottom triangle as isosceles, this means that y = z, so
y+z = 64
y+y = 64
2y = 64
y = 64/2
y = 32
making z = 32 as well
Similarly, angle 1 and angle 4 are 32 degrees because the 116 angle is opposite the top left-most angle, and congruent to this angle. In other words, the bottom triangle is a mirror image of the top triangle.
The figure is a rhombus because all four sides are the same length (as shown by the tickmarks)
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Answer:
This figure is a rhombus
All four angles (angle 1 through angle 4) are the same measure. They are each 32 degrees
Answer:sin =perpendicular/hypotenuse
Step-by-step explanation:
Sin angle is given use tan theta or cos theta to find the RS
Answer:
$98.75
Step-by-step explanation:
50×75÷100 = 37.5 + 50 = 87.5
87.5 × 30 ÷ 100 = 26.5
87.5 - 26.5 = 61.25
87.5 + 61.25 = 148.75
148.75 - 50 = 98.75
i hope i am right
Answer:
Part A
Which is the ordered pair for Point B?
A. (2, 8)
B. (6, 8)
C. (6, 6)
D. (8, 6)
Part B
Which point is at (8, 2)?
A. A
B. B
C. C
D. None of these
Part C
What are the coordinates of point A?
Enter your answer in the boxes.
(
2
,
8
)
Part D
What are the coordinates of the fourth vertex of the rectangle?
Enter your answer in the boxes.
(
0
,
0
)Step-by-step explanation:
Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
