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olga_2 [115]
3 years ago
6

A polynomial function with zeros 1,6i, and -6 i is

Mathematics
1 answer:
barxatty [35]3 years ago
8 0

Step-by-step explanation:

If -5 is a zero, then one of the factors must be (x+5). Typically, a problem will give you one complex root (zero), but you must infer that its conjugate is always another root. In this case, since 2+6i is a root, then 2-6i must also be a root.

Those factors must then be (x-(2+6i)) and (x-(2-6i))

To get the final polynomial, multiply the factors together: (x+5)(x-2-6i)(x-2+6I)

I would multiply the complex factors first since they will typically simplify to a more workable expression.

(x - 2 - 6i)(x - 2 + 6i) = x2 - 2x + 6xi - 2x + 4 - 12i - 6xi + 12i - 36i2

= x2 - 4x + 40

Then multiply this trinomial by the final factor: (x2 - 4x + 40)(x + 5)

= x3 + 5x2- 4x2- 20x + 40x + 200

= x3 + x2 + 20x + 200

To get a coefficient of 3, multiply this polynomial by 3.

3(x3 + x2 + 20x + 200) = 3x3 + 3x2 + 60x + 600

Answer: 3x3 + 3x2 + 60x + 600

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