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yawa3891 [41]
3 years ago
10

I don’t know how to do this

Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

Option 1

Step-by-step explanation:

\sqrt[4]{ {a}^{6}  {b}^{4}  {c}^{8}  } \\   = {a}^{6  \div 4}  {b}^{4 \div 4}  {c}^{8 \div 4} \\ which \: gives \: option \: 1

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4 years ago
Elena divided a decimal by a whole number. 84.36 ÷ 12 = ? Part A: Explain each step needed to divide 84.3y by 12. Part B: What i
Iteru [2.4K]

Answer:

Part A. \frac{84.3y}{12} = 7 +\frac{0.1\cdot y}{4}

Part B. The correct quotient is (3 × 4)

Step-by-step explanation:

Part A.

To divide 84.36 by 12 we look for the Highest Common Factor of the whole number and the decimal portions of the numerator and the denominator individually as follows;

\frac{84.36}{12} = \frac{84+0.3636}{12}  =  \frac{2 \times 2 \times 3  \times 7+0.01\times 12\times 3}{12} =  \frac{12  \times 7+0.03\times 12}{12}

Therefore, dividing 84.36 by 12 gives \frac{12  \times 7+0.03\times 12}{12} = 7+0.03 = 7.03

When dividing 84.3·y by 12, therefore, we have;

\frac{12  \times 7+0.3\times y}{12} = 7 +\frac{0.1\cdot y}{4}

Part B.

The correct quotient should have factors of the numerator

Therefore the divisor 12 should be represented as follows

\frac{12  \times 7+0.3\times y}{12} =\frac{12  \times 7+0.3\times y}{3 \times 4}

The correct quotient therefore = (3 × 4)

7 0
3 years ago
First: Four more than the product of a number and three
miss Akunina [59]
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2(8+x)

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3 0
4 years ago
A pond had an initial population of 120 fish. The number of fish is exponentially decreasing by one-fourth each year. If y repre
Kruka [31]
<span>1) Number of fish in the pond: y
Number of years: x

</span>A pond had an initial population of 120 fish. Then when x=0, y=120. The graph must begin at point (x,y)=(0,120). Only the graph above at right and below at left begin in this point (0,120).

<span>The number of fish is exponentially decreasing by one-fourth each year. Then the first year the number of fish must decrease 120*(1/4)=120/4=30, and the number of fish after the first year must be:
</span>120-30=90=120(1-1/4)=120(4-1)/4=120(3/4). Then when x=1, y=90. The point is (x,y)=(1,90)
In the graph above at right when x=1, y is between 24 and 36. y=90 is not in this interval. then this graph is not the correct.
In the graph below at left when x=1, y is between 84 and 96. y=90 is in this inverval. Then this is the correct graph.

Answer: T<span>he graph of the solution set for this situation is the graph below at left.

2) The equation has the form:
y=y0(r)^x
Where y0 is the initial population and r is the rate of reduction. In this case:
y0=120 and
r=1-1/4=(4-1)/4→r=3/4
Then the equation modeled by the graph is:
y=120(3/4)^x

Answer: The equation modeled by the graph is that above at right:
y=120(3/4)^x</span>
7 0
4 years ago
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