Ask question

Ask question

All categories

3 years ago

5

The table shows the amount of sugar needed to make lemonade. Are the quantities proportional? Explain which method you used and

how you used it to determine if they were proportionate or not.
Sugar (grams)

4

6

8

10

Servings

2

3

4

5

2 answers:

Klio2033 [76]3 years ago

7 0

Answer: Yes

Step-by-step explanation:

For the first sugar and servings part, 4 for sugar, 2 for servings.

The ratio for this example above it for sugars to servings it 2:1. So every 2 sugars is every 1 serving and this applies to every other of the sugars and servings in the table.

Mrrafil [7]3 years ago

6 0

Yes there are propotional.

If you pair them up in proportions:

4/2

6/3

8/4

10/5

If you divide them all you get 2 and that means they are all proportional

You might be interested in

Right Triangle Trig.

d1i1m1o1n [39]

The values are vx = $\frac{14\sqrt{3} }{\sqrt{2} }$ , vw = $\frac{14\sqrt{3} }{\sqrt{2} }$ and m∠x = 45°, for the given right angle diagram.

Step-by-step explanation:

The given is,

Right angled triangle XVW,

XW = 14 $\sqrt{3}$

m∠V = 90°

m∠W = 45°

Step:1

Given diagram is right angle triangle,

Trigonometric ratios for right angle is,

$sin$ ∅ $=\frac{Opp}{Hyp}$ ............................(1)

$cos$ ∅ $= \frac{Adj}{Hyp}$ .........................(2)

$tan$ ∅ $= \frac{Opp}{Hyp}$ ..........................(3)

Step:2

For the value of VX,

$sin$ ∅ $=\frac{VX}{XW}$

From given,

∅ = 45°

XW = 14 $\sqrt{3}$

Above equation becomes,

$sin$ 45 $=\frac{VX}{14\sqrt{3} }$

Where, Sin 45 = $\frac{1}{\sqrt{2} }$ ,

$\frac{1}{\sqrt{2} } = \frac{VX}{14\sqrt{3} }$

$VX = \frac{14\sqrt{3} }{\sqrt{2} }$

Step:3

For the value of VW,

$cos$ ∅ $=\frac{VW}{XW}$

From given,

∅ = 45°

XW = 14 $\sqrt{3}$

Above equation becomes,

$cos$ 45 $=\frac{VW}{14\sqrt{3} }$

Where, cos 45 = $\frac{1}{\sqrt{2} }$ ,

$\frac{1}{\sqrt{2} } = \frac{VW}{14\sqrt{3} }$

$VW = \frac{14\sqrt{3} }{\sqrt{2} }$

Step:4

For the value m∠x = a,

$tan$ a $=\frac{VX}{VW}$

From given,

VX = $\frac{14\sqrt{3} }{\sqrt{2} }$

VW = $\frac{14\sqrt{3} }{\sqrt{2} }$

Above equation becomes,

$tan$ a $=\frac{\frac{14\sqrt{3} }{\sqrt{2} } } {\frac{14\sqrt{3} }{\sqrt{2} } }$

$tan$ a = 1

a = $tan^{-1}$ (1)

a = 45°

m∠x = a = 45°

Step:5

Check for solution,

m∠v = m∠w + m∠x

= 45° + 45°

90° = 90°

Result:

The values are vx = $\frac{14\sqrt{3} }{\sqrt{2} }$ , vw = $\frac{14\sqrt{3} }{\sqrt{2} }$ and m∠x = 45°, for the given right angle diagram.

5 0

4 years ago

Write an exponential function that passes through the points (0, 3) and (-1, 6)

FinnZ [79.3K]

Standard form of an exponential function is y=ab^x
when x=0, y=3, 3=ab^0, so you can figure out that a=3
when x=-1, y=6, 6=3b^(-1), b^(-1)=2, b=1/2
so the equation is y=3(1/2)^x

3 0

3 years ago

Examine the right triangle. What is the length of the hypotenuse, c? <br> Answers are in the pic

Olenka [21]

a^2+b^2=c^2 <----- the equation to find out sides for a right triangle

7 0

3 years ago

Read 2 more answers

Round 9296 to the nearest hundred?

Fittoniya [83]

The answer is 9300

Hope this helped :)

8 0

3 years ago

Read 2 more answers

Find the 60th term of the following sequence.<br> 2, 4, 6...

Helen [10]

Answer:

Answer is <em>120</em>

Step-by-step explanation:

$here \: all \: the \: terms \: goes \: in \: the \: multiple \: \\ of \: 2 \\ therefore \: {n}^{th} \: term \: is \: 2n \\ when \: n = 1 \: we \: get \: 2 \times 1 = 2 \\ to \: find \: {60}^{th} \: term \: on \: substituting \: n = 60 \: in \: 2n \\ 2 \times 60 = 120 \\ hence \: {60}^{ th} \: term \: is \: 120$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0

3 years ago