Question

Find the inverse of g(n) = - 3 - 1

Answer 1

Answer:

$g'(n) = -\frac{n+1}{3}$

Step-by-step explanation:

Given

$g(n) = -3n - 1$

Required

Determine the inverse

$g(n) = -3n - 1$

Replace g(n) with y

$y = -3n - 1$

Swap positions of x and y

$n = -3y - 1$

Make y the subject

$3y = -n - 1$

$3y = -(n + 1)$

$y = -\frac{n+1}{3}$

Replace y with g'(n)

$g'(n) = -\frac{n+1}{3}$