Answer:
2
Step-by-step explanation:
let x be how much longer she can run the race and still beat her previous time
55(min) + x(min) < 1(hr) + 10(min)
55(min) + x(min) < 60(min) + 10(min)
55 + x < 60 + 10
x < 60 + 10 - 55
x < 15(min)
Answer:
The percent decrease is approximately 
(Don't know what you are expected to round to.)
Step-by-step explanation:
Percent change can be calculated by doing:

Then you multiply the result to covert it to a percentage.
Let's use this formula:




approximately
Now the answer as a percent is
approximately.
The percent decrease is approximately 
-9-6+12h+40=22
12h+25=22
12h=-23
h=-23/12