Question

A restaurant offers three sizes of coffee and four differerſt types of coffee.

Answer 1

Answer:  864

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Work Shown:

There are,

• 3 sizes of coffee
• 4 types of coffee
• 2 choices for cream (you pick it or you leave it out)
• 2 choices for sugar (same idea as the cream)

This means there are 3*4*2*2 = 12*4 = 48 different coffees. We'll use this value later, so let A = 48.

There are 6 bagel options. Also, there are 3 choices in terms of if you order the bagel plain, with butter, or with cream cheese. This leads to 6*3 = 18 different ways to order a bagel. Let B = 18.

Multiply the values of A and B to get the final answer

A*B = 48*18 = 864

There are 864 ways to order a coffee and bagel at this restaurant.

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If you're curious why you multiply the values out, consider this smaller example.

Let's say you had 3 choices of coffee and 2 choices for a bagel. Form a table with 3 rows and 2 columns. Place the different coffee choices along the left to form each row. Along the top, we'll have the two different bagel choices (one for each column).

This 3 by 2 table leads to 3*2 = 6 individual table cells inside. Each cell in the table represents a coffee+bagel combo. This idea is applied to the section above, but we have a lot more options.