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aliina [53]
3 years ago
6

PLEASEEE HELP FAST

Mathematics
1 answer:
Viktor [21]3 years ago
4 0

Answer:

1. 4 as that is when he is closest.

2. 3 is when he is waiting as the graph is horizontal showing no movement

3. 4 would change as that is showing his pace walking home if it increased the slope would become steep but if it decreased it would level out more.

Step-by-step explanation:

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Y=-3x+5 5x - 4y= -3 solvining systems of equations by substitution
andreyandreev [35.5K]
\left\{\begin{array}{ccc}y=-3x+5\\5x-4y=-3\end{array}\right\\\\\\substitute\\\\5x-4(-3x+5)=-3\\5x+12x-20=-3\\17x-20=-3\\17x=-3+20\\17x=17\ \ \ \ /:17\\x=1\\\\y=-3\cdot1+5=-3+5=2\\\\  \left\{\begin{array}{ccc}x=1\\y=2\end{array}\right
4 0
3 years ago
Which ordered pair is the solution set of 1x-7y>7
Brrunno [24]

Answer:

x>7y+7

Step-by-step explanation:

6 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Can someone please help me with these 2 problems. With work please & thank u
Triss [41]

Answer:

I'm not good with the type of math on 3, so I'm going to answer 4. (P.S I don't know the question you're asking, so I'm going to assume you want to know the area and perimeter of the shapes.

Step-by-step explanation:

To solve number 4 I added the width of the 2 triangles to give me the width of the rectangle, so then 2 times 9 is 18. Then for the triangles. The formula for triangles is base times height divided by 2. So we add the areas of all shapes and we get: 18+6+24=48m. So the area for number 4 is 48 meters.

(hope this was your question)

4 0
3 years ago
Please solve pleaseeee
Step2247 [10]

Step-by-step explanation:

7x + 3x + 90= 180

10x= 180-90

10x= 90

x= 90/10

x=10

4 0
3 years ago
Read 2 more answers
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