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Hitman42 [59]
3 years ago
5

I need help please???

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

1st pair: -7 and 3

2nd pair: -5 and 1

3rd pair: -3 and -1

Step-by-step explanation:

They all equal -4

zimovet [89]3 years ago
4 0

Answer:

(-7 and 3) (-5 and 1) (-3 and -1)

Step-by-step explanation:

If you add all of them you get -4.

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An irrational number between -2 and -1<br><br> a rational number between -2 and -1
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Answer:

An irrational number between -2 and -1 would be \frac{-\pi }{2}

A rational number between -2 and -1 would be -1.5

Step-by-step explanation:

\frac{-\pi }{2} = -1.570796... This number does not have repeating decimals, patterns, and it isn't a terminating decimal. It is irrational.

-1.5 is a terminating decimal, therefore it is rational, as well as between -2 and -1.

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You rent an apartment that costs $1800 per month during the first year, but the rent is set to go up 9.5% per year. Write a recu
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1800 a month, that’s expensive, 9.5 percent per year. Wow
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Wich state is the farthest state in the southwest region​
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Step-by-step explanation: Alaska is the farthest state in the southwest region​.

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3 years ago
In order to solve the following system of equations by addition, which of the
Pavlova-9 [17]

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given <u>system of equations</u>:

\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>.  To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.

<u>To eliminate the </u><u>variable y</u>:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

\implies -3(4x-2y=7) \implies -12x+6y=-21

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

\implies 2(3x-3y=15) \implies 6x-6y=30

Add the two equations together to <u>eliminate y</u>:

\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}

<u>Solve</u> for x:

\implies -6x=9

\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}

<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:

\implies 3\left(-\dfrac{3}{2}\right)-3y=15

\implies -\dfrac{9}{2}-3y=15

\implies -3y=\dfrac{39}{2}

\implies y=-\dfrac{39}{2 \cdot 3}

\implies y=-\dfrac{13}{2}

Learn more about systems of equations here:

brainly.com/question/27868564

brainly.com/question/27520807

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