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tia_tia [17]
3 years ago
5

Write the equations for a line parallel to the line:

Mathematics
2 answers:
Dmitrij [34]3 years ago
5 0

Answer:

y = -4/3x -46/3

Step-by-step explanation:

The question tells us to write an equation that is:

- parallel to the given line

- goes through the point (-7, -6)

Parallel lines will have the same slope, because if the slope was different, they would eventually intersect and not be parallel lines anymore.

We are going to use the point-slope form to find the other line.

Point-slope form uses a point that the graph will cross through and the slope of the graph to find the graph in y = mx + b form (also called slope-intercept form).

(I attached the point-slope form as an image below)

m = slope

x1 = x coordinate of the point

y1 = y coordinate of the point

We are going to substitute our slope into the form first:

y - y1 = (-4/3)(x - x1)

Next let's put in our point (-7, -6):

(Remember! -7 is our x coordinate & -6 is our y coordinate :-) )

y - (-6) = -4/3(x - (-7))

(cancel out the negatives to make them positive)

y + 6 = -4/3 (x +7)

Now solve for x using basic algebra:

y + 6 = -4/3 (x +7)

(distribue the -4/3)

y + 6 = -4/3x - 28/3

(subtract 6 from both sides)

y = -4/3x -46/3

That's your answer!

Hope it helps (●'◡'●)

madam [21]3 years ago
4 0

Answer:

Step-by-step explanation:

y + 6 = -4/3(x + 7)

y + 6 = -4/3x - 28/3

y + 18/3 = -4/3x - 28/3

y = -4/3x - 46/3

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In triangle ABC, angle = 90 degrees. AC = 7, BC = 12. AB = _______ Measure of angle A = _______ Measure of angle B = _______
Ulleksa [173]

Answer:

AB = 13.89

Measure of angle A = 59.74°

Measure of angle B = 30.26°

Step-by-step explanation:

The given parameters are;

∠C = 90°

AC = 7

BC = 12

Part 1

Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)

From Pythagoras theorem, we have;

A² = B² + C²

Where, A is the opposite side to the right angle, hence;

In the ΔABC,

AB ≡ A

Therefore;

AB² = AC² + BC² = 7² + 12² = 193

∴ AB = √193 = 13.89

Part 2

∠A is the side opposite side BC such that by trigonometric ratios

tan \angle A = \frac{Opposite \, side \,  to \,  angle \,  A}{Adjacent  \,  side  \, to  \, angle \,  A}  = \frac{BC}{AC} = \frac{12}{7} = 1.714

∴ ∠A = Arctan(1.714) or tan⁻¹(1.714) = 59.74°

Part 3

∠B is found from knowing that the sum of the angles in a triangle = 180°

∴ ∠A + ∠B + ∠C = 180° which gives

59.74° + 90° + ∠B = 180°

Hence, ∠B = 180° - (59.74° + 90°) = 180° - 149.74° = 30.26°.

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