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givi [52]
2 years ago
13

The process of moving a figure to a different location is called:

Mathematics
1 answer:
Kisachek [45]2 years ago
5 0
The process of moving a figure to a different location is called TRANSFORMATION. 
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Divide. −36/−8 Enter your answer as a mixed number, in simplified form, in the box.
Pavel [41]

Answer:

= 4 whole  1/2

Step-by-step explanation:

Given that:

= −36/−8

"-" signs will be cancelled out with each other so

= 36/8

By reducing to lowest term

= 9/2

When writing into mixed form:

quotient = 4,   remainder = 1,  divisor = 2  so:

= 4  1/2

i hope it will help you!

8 0
3 years ago
Anything that ends in 5 can be divided by
Mandarinka [93]

Answer:

1, itself, and 5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Which expression can be used to find m pls help
natali 33 [55]

Answer:

∠ U = 22.62°

Step-by-step explanation:

We can use the trigonometric expression to find ∠U by using the ratio:

sin(θ) = opposite/ hypotenuse

=> sin ∠U = 7.5/ 19.5

=> ∠ U = sin^{-1}( 7.5/ 19.5)

∴ ∠ U = 22.619° ≈ 22.62°

5 0
2 years ago
On a coordinate plane, what is the difference between (-2,7) and (-2,-6)?
Shtirlitz [24]
If you mean distance, then we can use the distance formula to find out.

(x - x)² + (y - y)² = d²   Distance formula
(-2 + 2)² + (7 + 6)² = d²   Substitute the points; remember that when you subtract a negative, you add, and also remember to always subtract in the same direction (with the points (1,2) and (3,4), if you do 1 - 3, then do 2 - 4 and not 4 - 2)
(0)² + (13)² = d²   Add
0 + 169 = d²   Square
169 = d²   Add
13 = d   Take the square root of both sides to cancel out the exponent

The distance between (-2,7) and (-2,-6) is 13 units.

Hope this helps!
4 0
2 years ago
4) Solve each pair of simultaneous equations.
Mkey [24]
4) a. x+y=1–(1)
y=2x-8—(2)
(2) into (1)
x+(2x-8)=1
3x-8=1
3x=1+8
x=9/3
x=3—(3)
(3) into (2)
y=2(3)-8
y=-2

ans x=3, y=-2

b. x+y=19—(1)
y=5x+1—(2)

(2) into (1)

x+(5x+1)=19
6x+1=19
6x=19-1
x=18/6
x=3—(3)

(3) into (2)

y=5(3)+1
y=16

ans x=3, y=16

c.x+y=-2—(1)
y=x-10—(2)

(2) into (1)

x+(x-10)=-2
2x-10=-2
2x=-2+10
x=8/2
x=4–(3)

(3) into (2)
y=4-10
y=-6

ans x=4, y=-6


5) 3x=y—(1)
x=y-16–(2)

(2) into (1)

3(y-16)=y
3y-48=y
2y=48
y=48/2
y=24–(3)

(3) into (2)

x=24-16
x=8

ans x=8, y=24
7 0
2 years ago
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