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julsineya [31]
3 years ago
11

I needddd helppp please help meee..

Mathematics
2 answers:
snow_tiger [21]3 years ago
7 0
Hey is this jasmine?
Sunny_sXe [5.5K]3 years ago
4 0
Bro jasmine. ??? This is crazy
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Suppose a simple random sample of size n = 14 is obtained from a population with μ = 61 and σ = 17.
sergejj [24]

Answer:

C. The population must be normally distributed.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For us to apply the central limit theorem with a sample size of 14, the underlying population must be normally distributed.

So the correct answer is:

C. The population must be normally distributed.

5 0
3 years ago
Find the difference. Write in simplest form.7/8-2/8=
Phantasy [73]
Simple, all you want to do is subtract. 7-2=5; and denominators are not subtracted thus it would be 5/8. And that is the simplest form already 5/8.
7 0
3 years ago
May someone please help me, please? This is about exponents by the way. About 5 questions I need help with.
Leno4ka [110]

Answer:

1. 1  

2. 1

3. 16/81

4. 3

5. 3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What decimal is represented by this expanded form? 3X1000 + 6X100 + 1X10 + 2X1/10 + 1X 1/1000
Nata [24]
3000 + 600 + 10 + 0.2 + 0.001

= 3,610.201  answer
5 0
3 years ago
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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
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