4a+10=38 solve the equation
2 answers:
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Answer:
a) We need to check two conditions:
1)
2)
So we satisfy the two conditions so then we have a probability distribution
b)
And we can use the complement rule and we got:
c)
d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.
Step-by-step explanation:
For this case we have the following probability distribution given:
C 0 1 2 3 4 5 6 7 8
P 0.05 0.14 0.34 0.24 0.11 0.07 0.02 0.02 0.01
And we assume the following questions:
a) Verify that this is a probability distribution
We need to check two conditions:
1)
2)
So we satisfy the two conditions so then we have a probability distribution
b) What is the probability one randonmly chosen classmate has at least one child
For this case we want this probability:
And we can use the complement rule and we got:
c) What is the probability one randonmly chosen classmate has no children
For this case we want this probability:
d) Look at the answers for parts b and c and explain their relationship
For this case we see that the result from part b use the probability calculated from part c using the complement rule.