. Multiplying the denominator by 
gives
Subtracting this from the numerator gives a remainder of
. Multiplying the denominator by 
gives
and subtracting this from the previous remainder gives a new remainder of
This last remainder is exactly the same as the denominator, so 
divides through it exactly and leaves us with 1.
What we showed here is that
and this last expression is the quotient.
To verify this solution, we can simply multiply this by the original denominator:
which matches the original numerator.
Ax + By = C form of the given equation is –6x + y = –28.
Solution:
Given equation is y – 2 = 6(x – 5).
To write the equation in Ax + By = C format:
y – 2 = 6(x – 5)
y – 2 = 6x – 30
Add 2 on both sides of the equation.
y – 2 + 2 = 6x – 30 + 2
y = 6x – 28
Subtract 6x from both sides of the equation.
y – 6x = 6x – 28 – 6x
y – 6x = –28
Arrange the terms in the equation.
–6x + y = –28
This is in the form of Ax + By = C.
Here A = –6, B = 1 and C = –28.
C I think so sorry if I’m wrong
UW is always equal to 9x-9 or 9(x-1) whenever x is a real number. By adding in x, we can get the value.
For example, if x was 4, we add in x, giving us 9*4-9=36-9=27 units or
9(4-1)=9(3)=27 units
Hoped this helped in time!
