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bija089 [108]
3 years ago
7

How do you do these?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
\bf 6\sqrt[4]{405}\quad now\to 
\begin{cases}
405\to 3\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 3^4\cdot 5
\end{cases}
\\ \quad \\
6\sqrt[4]{3^4\cdot 5}\implies 6\cdot 3\sqrt[4]{5}\\
----------------------------\\
\bf 3\sqrt{49x^9y^{16}}\quad now\to 
\begin{cases}
49\to 7\cdot 7\to 7^2\\
x^9\to x^{2+2+2+2+1}\\
\qquad  x^2\cdot x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^4\cdot x\\
y^{16}\to y^{2+2+2+2+2+2+2+2}\\
\qquad y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad \cdot y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad (y^2)^8
\end{cases}
\\ \quad \\
3\sqrt{7^2(x^2)^4x(y^2)^8}\implies 3\sqrt{7^2(x^4)^2x(y^8)^2}
\\ \quad \\
3\cdot 7\cdot x^4\cdot y^8\sqrt{x}\implies 21x^4y^8\sqrt{x}
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Answer:

-7 4/5 or -7.8

Step-by-step explanation:

Product means multiplication

( - 13/8 )( 24/5)

= (-13 · 24)/(8 · 5)    negative · positive = negative

= - 312/40

=  -7  32/ 40 = -7 4/5 or 7.8

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3 years ago
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
ch4aika [34]

Answer:

\ln x+\frac{1}{3}\ln (x^2+1)

Step-by-step explanation:

Consider the given expression is

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Using the properties of logarithm we get

\ln x+\ln (x^2+1)^{\frac{1}{3}}         [\because \ln (ab)=\ln a+\ln b]

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Therefore, the simplified form of the given expression is \ln x+\frac{1}{3}\ln (x^2+1).

6 0
3 years ago
Determine the constant of variation for the direct variation given. Type a numerical answer in the space provided.
Andreyy89

Answer:

B. 4

Step-by-step explanation:

Determine the constant of variation for the direct variation given.

(0, 0), (3, 12), (9, 36)

A. 3

B. 4

C.12

Direct variation is given by:

y = kx

Where,

k = constant of variation

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x = 3; y = 12

y = kx

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y = kx

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36 = 9k

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