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bija089 [108]
3 years ago
7

How do you do these?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
\bf 6\sqrt[4]{405}\quad now\to 
\begin{cases}
405\to 3\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 3^4\cdot 5
\end{cases}
\\ \quad \\
6\sqrt[4]{3^4\cdot 5}\implies 6\cdot 3\sqrt[4]{5}\\
----------------------------\\
\bf 3\sqrt{49x^9y^{16}}\quad now\to 
\begin{cases}
49\to 7\cdot 7\to 7^2\\
x^9\to x^{2+2+2+2+1}\\
\qquad  x^2\cdot x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^4\cdot x\\
y^{16}\to y^{2+2+2+2+2+2+2+2}\\
\qquad y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad \cdot y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad (y^2)^8
\end{cases}
\\ \quad \\
3\sqrt{7^2(x^2)^4x(y^2)^8}\implies 3\sqrt{7^2(x^4)^2x(y^8)^2}
\\ \quad \\
3\cdot 7\cdot x^4\cdot y^8\sqrt{x}\implies 21x^4y^8\sqrt{x}
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2(x+4) = 12 find the value of x i need help plz
saveliy_v [14]

Answer:

x = 2

Step-by-step explanation:

2(x+4)=12

2x+8=12........multiplying each number in the bracket by 2

2x = 12-8

2x = 4...... dividing both sides by 2

x = 2

6 0
3 years ago
Find the indicated limit, if it exists.
jok3333 [9.3K]
For the limit to exist, the limits from either side must also exist and be identical. We have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1

Since the limits do not match, the overall limit does not exist.
6 0
3 years ago
Here are two rectangles.
jolli1 [7]

Answer:

1/1/3 is the answer “ one and one third

Step-by-step explanation:

to find length scale factor,

take the length of the 2nd triangle and divide it by the length of the first triangle,

you'll get the length scale factor

6 0
3 years ago
Read 2 more answers
13 POINTS HELP ME PLEASE
My name is Ann [436]
X= 13.5

Every triangle equals 180 degrees. 23+23= 46. 46 - 1= 45. Then you solve the equation 10x+45=180 which would equal, 13.5.
8 0
3 years ago
Read 2 more answers
1-cos(6x)=___?<br> A. 3sin(2x)<br> B. 2sin^2(3x)<br> C. 3cos(2x)<br> D. 2cos^2(3x)
zhenek [66]

The solution to 1 - cos(6x) is 2sin²(x).

Hence, option B) 2sin²(x) is the correct answer.

<h3>What is solution to 1 - cos(6x)?</h3>

Given that; 1 - cos(6x) = ?

First, we rewrite using trig identity

1 - cos(2 × 3x)

Using the double angle identity, { <em>cos2(x) = 1 - 2sin²(x)</em> }

1 - ( 1 - 2sin²(x) )

Eliminate the parentheses

1 - 1 + 2sin²(x)

2sin²(x)

The solution to 1 - cos(6x) is 2sin²(x).

Hence, option B) 2sin²(x) is the correct answer.

Learn more about trig identity here: brainly.com/question/10376944

#SPJ1

4 0
2 years ago
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