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bija089 [108]
3 years ago
7

How do you do these?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
\bf 6\sqrt[4]{405}\quad now\to 
\begin{cases}
405\to 3\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 3^4\cdot 5
\end{cases}
\\ \quad \\
6\sqrt[4]{3^4\cdot 5}\implies 6\cdot 3\sqrt[4]{5}\\
----------------------------\\
\bf 3\sqrt{49x^9y^{16}}\quad now\to 
\begin{cases}
49\to 7\cdot 7\to 7^2\\
x^9\to x^{2+2+2+2+1}\\
\qquad  x^2\cdot x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^4\cdot x\\
y^{16}\to y^{2+2+2+2+2+2+2+2}\\
\qquad y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad \cdot y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad (y^2)^8
\end{cases}
\\ \quad \\
3\sqrt{7^2(x^2)^4x(y^2)^8}\implies 3\sqrt{7^2(x^4)^2x(y^8)^2}
\\ \quad \\
3\cdot 7\cdot x^4\cdot y^8\sqrt{x}\implies 21x^4y^8\sqrt{x}
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Answer:

7

Step-by-step explanation:

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b=2

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Answer:

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Step-by-step explanation:

Here, we want to fill the boxes

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2 years ago
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sesenic [268]
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A number when divided by 780 gives remainder 38 .What
baherus [9]

Given:

A number when divided by 780 gives remainder 38.

To find:

The reminder that would be obtained by dividing same number by 26.

Solution:

According to Euclis' division algorithm,

a=bq+r                ...(i)

Where, q is quotient and 0\leq r is the remainder.

It is given that a number when divided by 780 gives remainder 38.

Substituting b=780,\ r=38 in (i), we get

a=(780)q+38

So, given number is in the form of 780q+38, where q is an integer.

On dividing 780q+38 by 26, we get

\dfrac{780q+38}{26}=\dfrac{780q}{26}+\dfrac{38}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26+12}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26}{26}+\dfrac{12}{26}

\dfrac{780q+38}{26}=30q+1+\dfrac{12}{26}

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