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bija089 [108]
3 years ago
7

How do you do these?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
\bf 6\sqrt[4]{405}\quad now\to 
\begin{cases}
405\to 3\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 3^4\cdot 5
\end{cases}
\\ \quad \\
6\sqrt[4]{3^4\cdot 5}\implies 6\cdot 3\sqrt[4]{5}\\
----------------------------\\
\bf 3\sqrt{49x^9y^{16}}\quad now\to 
\begin{cases}
49\to 7\cdot 7\to 7^2\\
x^9\to x^{2+2+2+2+1}\\
\qquad  x^2\cdot x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^4\cdot x\\
y^{16}\to y^{2+2+2+2+2+2+2+2}\\
\qquad y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad \cdot y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad (y^2)^8
\end{cases}
\\ \quad \\
3\sqrt{7^2(x^2)^4x(y^2)^8}\implies 3\sqrt{7^2(x^4)^2x(y^8)^2}
\\ \quad \\
3\cdot 7\cdot x^4\cdot y^8\sqrt{x}\implies 21x^4y^8\sqrt{x}
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A padlock has a four-digit code that includes digits from 0 to 9, inclusive. What is the probability that the code does not cons
Eduardwww [97]
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.

4 0
3 years ago
Read 2 more answers
If UT is a midsegment of QRS, find SQ<br> A. 8 <br> B. 10 <br> C. 16 <br> D. 20
sladkih [1.3K]
If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3

Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
8 0
3 years ago
A standard pair of six-sided dice is rolled. what is the probability of rolling a sum greater than 66? express your answer as a
777dan777 [17]

Answer:

a

Step-by-step explanation:

6 0
4 years ago
Determine the larger of two consecutive integers whose sum add to 85
Vesnalui [34]
N+(n+1) = 85. 2n+1=85, 2n=84. n=42. So the consecutive integers are 42 and 43, and the larger one is 43.
8 0
4 years ago
6. Find the total bill:
daser333 [38]

First multiply all the items up with their correct prices.

5 Golf Clubs = 18.65 each

5 x 18.65 = 93.25

60 Golf Balls = 16.50 per dozen

60 = 5 dozen

5 x 16.50 = 82.5

1 pair of golf shoes = 75.80

1 x 75.80 = 75.80

Now, add them all up.

93.25 + 82.5 + 75.80 = 251.55

Lastly, multiply by 1.15 to add the 15% sales tax.

251.55 x 1.15 = 289.28

Thus, the total cost of all the equipment with tax is $289.28

7 0
3 years ago
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