The point of observation is 2500 m away from the foot of the building.
The angle of elevation is 4°.
We need to find the height 'h' of the building.
With respect to 4°,
2500 is the adjacent side.
'h' is the opposite side.
The trigonometric ratio associating opposite & adjacent is tan.
We have


Cross multiplying we get
h = 2500 tan4°
h= 174.82 m
Option B) is the right answer.
Answer: Greater than 10 N
Step-by-step explanation:
Given
Gravity force on metal is 10 N
But the metal piece is rising i.e. there must be an upward force greater than 10 N
Suppose the force is F
So, we can write

Any force greater than 10 N is sufficient for the metal to move upwards
The greater the amount of force faster will be the movement
m5=75 degrees
m11=75 degrees
m16=65 degrees
To find 5, realize angles 5 and 8 equal 180, because they make up a straight line, line d.
180-105=75
To find 11, it is the same as finding 7. Just look at the similar sizes. Angle 7 is the same at angle 5, just turned around. There’s a term for this pair angles that I don’t remember now but it exists. Now, lines a and b are parallel, so their angles between lines that intersect both are the same too. This means, as angle 5 equals angle 7, angle 7 equals angle 11.
To find 16, we use a combination of the methods used in finding the previous angles.
180-115=65 degrees is angle 4
Angle 4=Angle 16
Knowing the two angles given and that lines a and b are parallel, you could find the measurements of every angle in each intersection if you wanted to.
I use a bit of a different looking formula.
A(t)=P(1+r/n)^nt
P=amount of money. (500)
r= rate (in decimal. 4%=0.04)
n=number of times per year (1 in this problem)
t=amount of time. (5 years)
Plugged in it looks like this:
A(t)=500 (1+ 0.04/1)^1x5
Then I put it into my calculator like this:
0.04/1+ 0.04
Then add one to the above answer:
0.04+1=1.04
Then raise the above answer to the 1x5:
1.04^5=1.2166......
Then multiply the above answer by 500:
1.2166.... x 500=608.3264512
She has $608 after 5 years.
Hope this helps, let me know if you have any questions.