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2 years ago

Which answer choice is equivalent to -65-12?

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

6 0

Answer:

Taht problem equals -77 so I would say d, good luck!

Alex17521 [72]2 years ago

5 0

I would say the answer would be d !

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Shelby mixes a 25% bleach solution with 5 cups of a 10% bleach solution, resulting in a 20% bleach solution. The table shows the

Tcecarenko [31]

Answer:

The value of x is 10

Step-by-step explanation:

We can use a system of equations to solve this.

Cups of 25% bleach solution used = x

Cups of 1-% bleach solution used = 5

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The first equation becomes:

x + 5 = y

Using the decimal forms of each percentage solution

25% solution for x cups = 0.25x

10% solution for 5 cups = 0.1(5)

20% solution for y cups = 0.2 y

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3 years ago

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Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.

larisa86 [58]

Answer:

a) $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

b) $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

c) $t_{\alpha/2}=-2.11$

d) $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is $\alpha=1-0.87=0.13$ and $\alpha/2 =0.065$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.065$ and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

Part b

On this case the confidence is 92% or 0.92 so the significance level is $\alpha=1-0.92=0.08$ and $\alpha/2 =0.04$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

$df=n-1=15-1=14$

We need values b,c on the t distribution with 14 degrees of freddom such that:

$P(t_{(14)}$ or $P(t_{(14)}>c)=0.04$ and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

Part c

The significance level is $\alpha=0.025$ and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

We need a value c on the t distribution with 17 degrees of freddom such that:

$P(t_{(17)}$ , and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values $t_{\alpha/2}=-2.11$

Part d

The significance level is $\alpha=0.08$ and $\alpha/2 =0.04$ . On this case we know that w ehave a two tailed proportion test, so we will have two critical values.