Answer:
-4.3
Step-by-step explanation:
5.4 +(-9.7)
= 5.4-9.7
=-4.3
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer:
10^0*10^1-1,
10^0*10^1*1^10,
10^0+10^1*1^10,10^0+10^1+1^10
Step-by-step explanation:
Answer:
−4<x<2
Step-by-step explanation:
−1<x+3<5
−1+−3<x+3+−3<5+−3 (Add -3 to all parts)
−4<x<2
