Can some one friend me plz

Two window washers start at the heights shown. One is rising, the other is descending. How long does it take for the two window

kvasek [131]

Answer:

After 18.32 seconds washer men will be at the same height.

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11 inches per second) one is rising one is descending. How long does it take for the two window washers to reach the same height? Explain

Two window washers are moving in opposite directions.

First window washer is at 21 ft and rising with the speed of 8 inches per second.

Second window washer is at 50 feet and descending with the speed of 11 inches per second.

Since 1 feet = 12 inches

Therefore, 21 feet = 21×12 = 252 inches

Similarly, 50 feet = 50 × 12 = 600 inches

Let both the window washer takes 't' time to be at the same height.

Height of the first window washer after t seconds = (252 + 8t) feet

Height of the second window washer after t seconds = (600 - 11t) feet

Since both are at the same height after time 't',

(252 + 8t) = (600 - 11t)

8t + 11t = 600 - 252

19t = 348

t = 18.32 seconds

Therefore, after 18.32 seconds washer men will be at the same height.

8 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

How do I solve this absolute value in quality problem |2t + 2/3|≤4

xenn [34]

Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

2t + 2/3≤4

(2t + 2/3≤4)*3

6t+2≤12

6t≤10

t≤10/6

t≤5/3

2t + 2/3>=-4

(2t + 2/3>=-4)*3

6t + 2>=-12

6t>=-14

t>=-14/6

t>=-7/3

-7/3≤t≤5/3

6 0

2 years ago

I don’t get this can someone please help me?

FinnZ [79.3K]

The price difference/ the original price and times the whole equation by 100 (to get the percentage).

> ($50/$150) x 100 = 33% (rounded)

7 0

2 years ago

Read 2 more answers

Can you help me find the value of x and y. I am very confused.

Monica [59]

Hello,
Let's assume top left corner: A
top right corner : B
Bottom right corner: C
Bottom left corner :D

M= middle of [CD]

ABM is a triangle rectangular isocel:

(3√2)²+(3√2)²=y²
==>y²=2*9*2
==>y²=36
==>y=6

The triangle BCM is rectangular with MB=3√2, MC=y/2=3
x²+3²=(3√2)²
==>x²=9*2-9
==>x²=9
==>x=3

8 0

2 years ago