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Likurg_2 [28]
2 years ago
10

Pls help I need this done in a few minutes!

Mathematics
2 answers:
larisa86 [58]2 years ago
8 0

Answer:

-2/5

Step-by-step explanation:

rise/run

BigorU [14]2 years ago
5 0
-2/5 if you do the rise over run you would see your answer
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ILL MARK BRAINLIEST!
Gre4nikov [31]

Answer:

Median

Step-by-step explanation:

Center of distribution is the middle of a distribution, much like the median. The median of a set of numbers is the number in the middle. Since these two are pretty similar, median would be the best to describe the centers of distribution out of the terms provided.

Edit: I'm leaning towards B.) Both aren't symmetrical

6 0
3 years ago
Complete y^2+15y+56=(y+7)(y+?) ...?
Rufina [12.5K]
The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:
y² + 15y + 56 = (y + 7)(y + a)
y² + 15y + 56 = y² + (7 + a)y + 7a
We can now compare the coefficient of the like terms, either the one with y or the one without y, and find the value of a.
15 = 7 + a; a = 8
OR
56 = 7a; a = 8

Second factor is (y + 8)
5 0
3 years ago
Read 2 more answers
Square inch for 30 stones
Anna71 [15]

1 stone = 20 square inches

1 stone * 30 = 20 square inches * 30

30 stones = 600 square inches

8 0
3 years ago
Proving triangles similar
goldfiish [28.3K]

Answer:

x=11

Step-by-step explanation:

You do 38/3x+3 and 19/x+7 and then cross mulitply and get 57x+57=38x+266. Then yoy subtract 57 from 266 and get 57x=38x+209. Now you have to subtract 38 from 57 and then answer will be 19. So now you have 19x=209. Finally you divide 209 by 19 and get x=11. Good luck!

6 0
3 years ago
If a 50 ft flagpole casts a 95 ft shadow, then how long is the shadow that a 5 ft tall of man casts ?
lesantik [10]

9.5 feet,to find that you must find out how many times longer the shadow of the pole is than the pole, and to do that you must divide 95 by 50, in which you get 1.9. And then to find the length of the shadow the man casts you must multiply his height by 1.9.

8 0
3 years ago
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