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myrzilka [38]
3 years ago
11

A regular convex polygon has eight sides. What is the measure of an exterior angle?

Mathematics
2 answers:
tigry1 [53]3 years ago
7 0

<u>Answer:</u>

Exterior angle = 45°

<u>Step-by-step explanation:</u>

We know that the sum of exterior angles of a polygon is 360 degrees.

Since here we a regular polygon with eight sides (which makes it an octagon) so this means that the interior angles each would be equal to:

\frac{(n - 2) \times 180}{n} \\ \frac{(8 - 2) \times 180}{8}\\ \frac{6 \times 180}{8} \\ \frac{1080}{8} = 135 degrees

We know that each interior angle is supplementary to the exterior angle at the vertex.

So each exterior angle = 180-135 = 45 degrees

PSYCHO15rus [73]3 years ago
4 0

Answer:

The measure of one exterior angle is 45 degrees.

Step-by-step explanation:

The formula to find exterior angle of and shape is 360 degrees divided by n (number of sides the shape has). 360 divided by 8 = 45 degrees.

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Answer:

6. x° is approximately 21.04°

7. x° is approximately 39.56°

8. x° is approximately 58.03°

9. x° is approximately 72.85°

Step-by-step explanation:

6. In the given right triangle (a triangle with the measure of one of the interior angles equal to 90°, indicated by the small square between two sides) , we have;

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cos\angle X = \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length}

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To find the value of x°, we make use of the inverse cosine function, arccos found on a scientific calculator, as follows;

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The length of the adjacent side to the given reference angle, x° = 23

By trigonometric ratios, we have;

Tan(\angle X) = \dfrac{Opposite \, side \  length}{Adjacent\, side \ length}

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sin\angle X = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

\therefore sin(x^{\circ}) = \dfrac{43}{45}

x° = arcsin(43/45) ≈ 72.85°

x° ≈ 72.85°.

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