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Grace [21]
4 years ago
15

Three different ways to make 12

Mathematics
2 answers:
victus00 [196]4 years ago
7 0
8x2 20-8 3x4 Hope it helped
iVinArrow [24]4 years ago
3 0
<span>2+10, 10+2 2+5+2+3, 5+2+2+3, 2+2+2+2+2+2, and 2+4+6 those are the ways to make 12.

If your talking multiplication, 1x12, 2x6, 3x4, 4x3, and 6x2.

 if your talking subtraction,  12-0, 13-1, 14-2, 15-3, 16-4, 17-5, 18-6, and 19-7.
hope you have found my answers useful
 


</span><span>
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Choose the ratio equivalent to 10/9
satela [25.4K]
<h3>Answer:</h3>

30/27, 20/18...

<h3>Solution:</h3>
  • There are <em>infinitely many ratios equivalent to 10/9.</em>
  • Here are <em>some </em>of them:
  • 30/27
  • 20/18
  • 100/90
  • 60/54

Hope it helps.

Do comment if you have any query.

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3 years ago
Work out the height of a parallelogram with base of 6cm and area of 27cm²
professor190 [17]
To find the height of the parallelogram you would divide 6 from the area, 27, to get the answer 4.5,
So h=4.5
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or round it to 2.2
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7 0
3 years ago
Can someone help me with this exercise?
olga2289 [7]

Answer:

View image

Step-by-step explanation:

You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.

Your first goal is to solve for y, which I did at the top.

And remember that when you divide/multiply by a negative number you have to flip the inequality sign.

So the first equation is already in term of y. (y < 2x + 4)

So you only have to solve for y for -3x - 2y ≥ 6.

I solved that and got y ≤ -3/2x - 3.

Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3

First you gotta treat it like a normal equation and graph them.

So i graphed y = 2x + 4 and y = -3/2x - 3. I assume you already know how do do that.

btw. < and > have dotted lines, while ≤ and ≥ have solid lines.

Now for the shading, you gotta look at the inequality sign.

y < 2x + 4 has a less than sign, so you have to shade everything underneath the line you graphed.

y ≤ -3/2x - 3 is also less than, so you have to shade everything underneath that line as well.

So in the future, you you get a > or ≥ then you have to shade above the graph.

5 0
3 years ago
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