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2 years ago

Can someone please show the work when doing this !

Mathematics

1 answer:

sleet_krkn [62]2 years ago

4 0

its already done in red

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What is 8x + -13x I just want to see if the answers are as quick as it says it is

Dafna1 [17]

- 5x.
In case you actually want to know how I got it:
the question is just saying "8x - 13x".
8 - 13 = -5

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3 years ago

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We know that Martin is buying some apples at $0.75 each and two dozen oranges

Daniel [21]

Step-by-step explanation:

0.75a + 2(0.90) = 27.60

is the correct answer

8 0

2 years ago

Simplify this expression.

Grace [21]

11x2 would be your answer.

6 0

3 years ago

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Maya drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 12 hours. When Maya drove

Roman55 [17]

Answer:

480 miles.

Step-by-step explanation:

Let x represent the distance between Maria's house and mountains ans r represent Maria's rate for going trip.

We have been given that there was heavy traffic on the way there, and the trip took 12 hours.

$\text{Distance}=\text{Rate}\times \text{Time}$

$x=12r$

We are also told that hen Maya drove home, there was no traffic and the trip only took 8 hours. Maria's average rate was 20 miles per hour faster on the trip home.

So Maria's speed while returning back would be $r+20$ .

$x=8(r+20)$

Upon equating both distances, we will get:

$12r=8(r+20)$

$12r=8r+160$

$12r-8r=8r-8r+160$

$4r=160$

$r=\frac{160}{4}$

$r=40$

Upon substituting $r=40$ in equation $x=12r$ , we will get:

$x=12r\\\\x=12(40)\\\\x=480$

Therefore, Maya live 480 miles away from the mountains.

7 0

3 years ago

Solve for x when <img src="https://tex.z-dn.net/?f=x%5E%7Byz%7D%20%3Dy%5E%7B2%7D" id="TexFormula1" title="x^{yz} =y^{2}" alt="x^

Assoli18 [71]

The value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

$x^{yz} = y^2$

Take the yz root of both sides

$\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}$

Apply the law of indices

$x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}$

Divide yz by yz

$x = \sqrt[yz]{y^2}$

Hence, the value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$