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Alja [10]
2 years ago
15

I NEED HELP WITH THIS FAST

Mathematics
1 answer:
padilas [110]2 years ago
7 0

Answer:

1a) 24,750

1b) 1.868

2a) 6870

2b) 15,371

3a) 1410

3b) 25,400

4a) 9709

4b) 1596

5a) 0.272

5b) 0.080

6a) 19,943

6b) 1.779

7a) 1.340

7b) 2986

8a) 5.618

8b) 22,252

9a) 18.873

9b) 0.37

10a) 14.981

10b) 2400

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Identify a number that results in a 4-digit-number when 156,350 is subtracted from it
jekas [21]

160,000 - 156,350 =3,650

7 0
2 years ago
Find three consecutive even numbers whose sum is 96?
stepladder [879]
So consectuve even numbers

we know that one even number plus 2= another even number so we want to find 3 consecutive even numbers that add up to 96 or
x is the first number
x+2 is the second number
x+4 is the third number

x+x+2+x+4=96
3x+6=96
subtract 6 from both sides
3x=90
divide both sides by 3
x=30

the first number is 30
x+2=32=second number
x+4=34=third number

the numbers are 30,32,34
3 0
3 years ago
Read 2 more answers
PLEASE HELP FASTT!!!!!!!<br> In a relation, the input values can also be referred to as the_____?
nika2105 [10]

Answer:

Domain

Step-by-step explanation:

3 0
3 years ago
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Event v occurs 28% of the time on Tuesdays.
vampirchik [111]

Answer:

68%

Step-by-step explanation:

Probability of occurrence of Event v = P(v) = 28% = 0.28

Probability of occurrence of both Events v and Event w together = P(v and w) = 19% = 0.19

We have to find what is the probability  that event w occurs with event v given that event v  occurs on a Tuesday. This is a conditional probability. In other words we have to find what is the probability of event w given that event v occurs of Tuesday. i.e we have to find P(w|v)

The formula to calculate this conditional probability is:

P(w|v) = \frac{P(v \cap w)}{P(v)}

Using the given values, we get:

P(w|v) = \frac{0.19}{0.28}\\\\ P(w|v) = 0.68\\\\ P(w|v) = 68\%

Therefore, the probability that even w will occur with event v given that event v occurs on Tuesday is 68%

7 0
3 years ago
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
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