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zheka24 [161]
3 years ago
12

Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table. A

2-column table with 4 rows is shown. The first column is labeled Blood Type with entries O, A, B, AB. The second column is labeled Number of People with entries 22, 20, 6, 2. Use the table to determine the following probabilities. The probability that a randomly chosen person from this group has type B is . The probability that a randomly chosen person from this group has type AB is . The probability that a randomly chosen person from this group has type B or type AB blood is
Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

3/25 for type B, 1/25 for type AB, and 4/25 for both

Step-by-step explanation:

O goes to 22

A goes to 20

B goes to 6

AB goes to 2

22+20+6+2 = 50, so (number of people with a certain blood type)/50 = the answers for each question.

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If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b
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Answer:

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Step-by-step explanation:

Let's start by using distributive multiplication:

(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd

So:

(5x-4)(3x+7)=15x^2+35x-12x-28\\\\

Grouping like terms:

15x^2 +(35x-12x)-28\\\\15x^2+23x-28

Now, 15x^2+23x-28 is equal to:

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15x^2+23x-28=15x^2-ax-b

In order to satisfied the equality:

23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)

Hence, from (1), let's solve for a:

23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23

And from (2), let's solve for b:

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Let's verify the result evaluating the values of a and b into the original equation:

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As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

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