There are multiple ways in which Anita can divide the sheet of paper for her calendar. First she can have it halved first then, divided by 6 or she can have it divided by 4 and divided each quarter by 3. Either way, each month would take up 1/12 of the total area of the paper.
Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Answer:
Converges at -1
Step-by-step explanation:
The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.
We will make use of integral by parts to determine:
let:





We can therefore determine that if x tends to 0 the limit is -1

It would shift up, that is the anwser