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Dafna1 [17]
2 years ago
6

How has the Roaring Twenties been portrayed in modern media? ​

Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0

Answer:

The nation's total wealth more than doubled between 1920 and 1929, and this economic growth swept many Americans into an affluent but unfamiliar “consumer society.” People from coast to coast bought the same goods (thanks to nationwide advertising and the spread of chain stores), listened to the same music

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Each side of a square is lengthened by 1 inch. The area of this new, larger square is 9 square inches. Find the length of a side
Savatey [412]

Answer:

91 EASY

Step-by-step explanation:

5 0
3 years ago
Anita uses 1 sheet of paper to make a calendar showing each month of the year. Draw Anita calendar. Show how she can divide her
hram777 [196]
There are multiple ways in which Anita can divide the sheet of paper for her calendar. First she can have it halved first then, divided by 6 or she can have it divided by 4 and divided each quarter by 3. Either way, each month would take up 1/12 of the total area of the paper. 
6 0
4 years ago
Read 2 more answers
a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske
Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1600, \pi = 0.4

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
4 years ago
if y=x + 5 were changed to y= x+ 9 how would the graph of the new function compare with the first one
WITCHER [35]

It would shift up, that is the anwser

7 0
4 years ago
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