Stot-S S. 10 12 Ahebdbdbebe

Mathematics

2 answers:

fenix001 [56]3 years ago

7 0

Answer:

THE HECK!?!?

Step-by-step explanation:

what are you even asking?

Sati [7]3 years ago

5 0

Answer:

10 its the right answer i hope because it shows

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Evaluate each expression using order of operations 40-32÷8+5×-2

klio [65]

Answer:

Step-by-step explanation:

40-32÷8+5×-2

40-4+5×-2

40-4+-10

36+-10

6 0

3 years ago

An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

sattari [20]

They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:

y=150-600t x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)

7 0

3 years ago

An observer in tower A sees a boat 1538 yd away at an angle of depression of 35°. To the nearest yard, how far is the boat away

Thepotemich [5.8K]

From my own solution, my answer is closest to D. 1951 yd; 27°

The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27°.

Pls. see my attachment.

In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin θ = opposite / hypotenuse

sin 35° = opposite / 1538 yd
sin 35° * 1538 yd = opposite
882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14°