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KatRina [158]
3 years ago
8

3/2 Find three rational numbers between and 5/2 ?​

Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{3*4}{2*4}=\frac{12}{8}\\\\\frac{5*4}{2*4}=\frac{20}{8}

Three rational numbers:

\frac{13}{8};\frac{14}{8};\frac{15}{8}

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Which expression is represented by the model? <br><br> A: x-3<br> B: x+3<br> C: -x-3<br> D: -x+3
Maurinko [17]

Answer:

the answer is D

Step-by-step explanation:

5 0
2 years ago
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Can anyone help me plz​
Kryger [21]

Answer:Ok

You need to get x by itself.

8x + c = k

Subtract c.

8x = k - c

Divide 8 from both sides.

x = k - c / 8

So, I believe it is D

Step-by-step explanation:

4 0
3 years ago
If f(x)=12x+2(x-1), find f(6)
zavuch27 [327]

Answer:

12x6+2(6-1)

72+2x5

72+10

82

82 is the answer.

Step-by-step explanation:

Just replace the X's in the problem with 6.

5 0
3 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
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