The product of two positive integers is always POSITIVE . The product of two negative integers is always POSITIVE. The product of a positive integer and a negative integer is always NEGATIVE . The product of any integer and –1 is always THE OPPOSITE OF THAT INTEGER .
I think the answer is.e=mc3
Make XY tables for each option.
If any of the Tables have identical X numbers it is not a function.
The first option has two X's that re 2, so is not a function.
Second option has 2 x's that are 4's, so is not a function.
The third option has no repeating X values so is a function.
The fourth option has two -2's and two 0's so ids not a function.
The function is the third choice:
On a coordinate plane, solid circles appear at the following points: (negative 3, 2), (negative 2, 2), (0, 1), (1, 3), (2, negative 4), (4, negative 1).
Answer:
The question is not so clear and complete
Step-by-step explanation:
But for questions like this, since the equation has been given, what is expected is for us to make comparison, compare the RHS with the LHS or by method of comparing coefficients.
We follow the stated conditions since we are told that b and c are both integers which are greater than 1 and b is less than the product of cb. from these conditions, we can compare and get the values of b , c and d.
Another approach is to assume values, make assumptions with the stated conditions, however, our assumptions must be valid and correct if we substitute the assumed values of b, c and d in the equation, it must arrive at the same answer for the RHS. i.e LHS = RHS
