A = .5 r^2 theta
Theta must be in radians
A = .5 (15.7)^2 (102)(pi/180)
A= 219 mm^2
Answer:
C
Step-by-step explanation:
The perimeter of the square has to be only positive values, and so there has to be restrictions on the values. We can rule out answers A and B. Because the perimeter the values of x have to be less than 4. If they were greater than 4, then 4x>16. So we can rule out answer d. The correct answer is C.
2/3 + 1/4 =4
this fraction could be added to 1/4 to get a sum greater than 1
Step-by-step explanation:
Divide two on both sides to get rid of it and the make the equation in the form y = mx + c
y = 3/2x + 5
since both lines are parallel they must have the same gradient which is 3/2
y = 3/2x + c
All you have to do now is to replace x and y with (2, -5) to find c
x = 2
y = -5
-5 = 3/2 × 2 + c
-5 = 3 + c
c = -5-3
c = -8
32/28 divide top and bottom by 4 =8/7
=1 1/7