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kotegsom [21]
4 years ago
6

Someone help me out please

Mathematics
2 answers:
Dimas [21]4 years ago
3 0

Answer:     2 to 1          and          2;1

Step-by-step explanation:

in general there are 3 ways to write these ratios. A fraction, the one using to, and the ones with semicolans. This is how you will always want to write your ratios on the problems you are solving with your ratios when it asks that.

bixtya [17]4 years ago
3 0

Answer:

\frac{2}{1}, 2:1,2

Step-by-step explanation:

We can actually use three forms here.

\frac{x}{y}

x:y

x to y.

Use the format for a ratio.

x:y

So

x=2 \\ y = 1

Now we can plug in.

\frac{2}{1} \\ \\ 2:1 \\ \\

2 to 1

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Fantom [35]
Answer is definitely C) 0
3 0
3 years ago
Math question, any help is appreciated &lt;3
lesya [120]

Since you already know the solution, you need to substitute every occurrence of x and y with those values: the first equation checks out, because it becomes

3\cdot 4 - 2 \cdot 2 = 12-4 = 8

The second becomes

2 \cdot 4 + 3 \cdot 2 = Q \iff 8+6 = Q \iff Q = 14

7 0
3 years ago
MATH SMARTIES I WILL GIVE BRAINLIEST (the highlighting was from my teacher btw) PLEASE GIVE EXPLINATION ALSO THANK YOU
EastWind [94]

Answer:

1) D.208

2) C.112

Step-by-step explanation:

so basically for 1 you solve the area for all the shapes you see in the net using the equation l*w=a and add them together

l= length

w=width

a=area

4*8=32

4*8=32

6*4=24

6*4=24

6*8=48

6*8=48

48+48+24+24+32+32=208

208cm^{2}

for number 2 since it's lateral surface area, you wanna find the area of all the shape in the net except for the square in the middle.

for the triangles you're gonna wanna use the equation 1/2b*h=a

b= base

h=height

a=area

7*4=28

7*4=28

7*4=28

7*4=28

28*4=112

4 0
3 years ago
PLZ HELP IM STRUGGLING!!
Cloud [144]

Answer:

1/3

Step-by-step explanation:

3 0
3 years ago
A conjecture and a portion of the flowchart proof used to prove the conjecture are shown.
Tasya [4]
Idk the answer but if you download an app called “ Photomath” it will help you solve your problem. It is completely free!
6 0
4 years ago
Read 2 more answers
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