Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
1/4 = x/360
4×9 = 36 so 4 × 90 = 360
also multiply the numerator by 90 and you get
1/4 × 90/90 = 90/360
Hello!
I believe that 36.90 as a fraction would be 369/10
I hope this helps!
35
35 is composite because it has more than one factor
1 3 7 35
35 / 2 is 17.5 so 35 is your answer
Answer:
-2 y
Step-by-step explanation:
