Answer:
3 - (n - 1) = 1/2(3n - 4)
Step-by-step explanation:
We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.
Let the number be n.
The first part is: three minus the difference of a number and one:
3 - (n - 1)
The second part is: one-half of the difference of three times the same number and four:
1/2(3n - 4)
Now, let us equate the first and second parts:
3 - (n - 1) = 1/2(3n - 4)
PS: I really do not understand the options
Answer:
yes
Step-by-step explanation:
so x=2 and y=5
5 = 5 x 2 - 5
0=0
equation is right
Answer:
Step-by-step explanation: I choose d because if you notice there are only 33 marbles in Bag F and Bag F-number of marbles is equal to 1/3 marbles = 11/33 marbles and Bag G contains only 11 marbles which are how many marbles there are in all bags.
January . . . $57.85
March . . . . 4 times as much = 4 (57.85) = $231.40
Deposit 78.45 more . . . ($231.40 + 78.45) = <em>$309.85</em> .
Notice that "interest" is never mentioned anywhere in this problem.
In other words, it doesn't matter whether Julie's savings account is
in a bucket in the basement, a mayonnaise jar on the porch, under
her mattress, or in a bank that pays no interest.
Without interest, $309.85 is what she <em><u>does</u></em> have<em><u /></em> in November, which
is about right for savings accounts in banks these days.
What her balance <em><u>should</u></em> be in November is an entirely different subject.
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 8
Putting x=1.5 in Eqn 1
Dividing both sides by 8
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
Learn more about elimination method at:
#LearnwithBrainly
