Draw a diagram to illustrate the problem as shown in the figure below.
Euclid is placed at the origin at (0,0).
Apollonius is 12 m north and 9 m east of Euclid, so its coordinate is (9,12).
Pythagoras is at the arbitrary position (x,y) so that is is at distance d from Euclid and 2d from Apollonius.
From the distance formula, obtain
d² = x² + y² (1)
(2d)² = (x-9)² + (y-12)²
or
4d² = (x-9)² + (y-12)² (2)
Substitute (1) into (2).
4(x² + y²) = x² - 18x + 81 + y² - 24y + 144
3x² + 3y² + 18x + 24y = 225
Divide by 3.
x² + 6x + y² + 8y = 75
Create perfect squares.
(x+3)² - 9 + (y+4)² - 16 = 75
(x+3)² + (y+4)² = 10²
Answer:
The path of Pythagoras is a circle of radius 10 m, centered at (-3, -4).
Because 5 in the main constant and there are 5 numbers, It will be 5 to the power of 5, so you will write it as 5^5
Answer:
x = 1.566
Step-by-step explanation:
7^2=12^x
- 7^2 means 7 squared, which is 7*7, which is 49.
49 = 12^x
- Now we have to use logarithms to figure this out! Logarithms are like the opposite of exponents.
Exponential: b^x = y
Logarithmic: logb(y) = x.
- Now with 49 = y, 12 = b, we plug in to get x:
logb(y) = x
log12(49) = x
Plug this in your calculator (on a TI-84, it's MATH -> A)
<u>x = 1.566</u>
9514 1404 393
Answer:
x = 3
Step-by-step explanation:
You can forget about point R. It does not have any part in this problem, except to add confusion.
The given line PQ has the same y-coordinate values for points P and Q. This means the segment is a horizontal segment. Its perpendicular bisector will be a vertical line through its midpoint.
The midpoint (M) of PQ is ...
M = (P +Q)/2
M = ((-2, 2) +(8, 2))/2 = (-2+8, 2+2)/2 = (6, 4)/2
M = (3, 2)
The vertical line through a point with x-coordinate 3 will have the equation ...
x = 3