You can think of this question like the photo attached above.
Hi!
I think for b, the answer would be:
You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.
I think for c, the answer would be:
You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.
Hope this helps! Best of luck!
Answer:
4+2
Step-by-step explanation:
PEMDAS
P for parentheses
Answer:
- D(5, 4), E(14, 7), M(9.5, 5.5)
Step-by-step explanation:
As AD = 1/4AB and DE ║ AC, the ratio CE/CB = 1/4, or CE = 1/4CB
<u>Find the coordinates of D:</u>
- x = 1 + 1/4(17 - 1) = 1 + 4 = 5
- y = 5 + 1/4(1 - 5) = 5 - 1 = 4
<u>Find the coordinates of E:</u>
- x = 13 + 1/4(17 - 13) = 13 + 1 = 14
- y = 9 + 1/4(1 - 9) = 9 - 2 = 7
<u>Find the coordinates of the midpoint M of DE:</u>
- x = (5 + 14)/2 = 19/2 = 9.5
- y = (4 + 7)/2 = 11/2 = 5.5
Answer:
x = +-sqrt(3) and they are the actual solutions
Step-by-step explanation:
x^2/ (2x-6) = 9/(6x-18)
get a common denominator of 6x-18
x^2/ (2x-6) * 3/3 = 9/(6x-18)
3x^2/ (6x-18) = 9/(6x-18)
since the denominators are the same, the numerators must be the same
3x^2 = 9
divide by 3 on each side
x^2 = 3
take the square root of each side
sqrt(x^2) = +-sqrt(3)
x = +-sqrt(3)
Answer:
a. 10
*the answer is in the photo I took*