I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
Let Home runs = X
Triples would be X-3 ( 3 less triples than home runs)
Doubles would be 3x ( 3 times as many doubles as home runs)
Singles would be 45(x-3) ( 45 times as many singles as triples)
Simplify the equation for singles to be 45x-153
Now you have X + x-3 + 3x + 4x-135 = 262
Simplify:
50x - 138 = 262
Add 138 to both sides:
50x = 400
Divide both sides by 50:
x = 400/50
x = 8
Home runs = x = 8
Triples = x-3 = 8-3 = 5
Doubles = 3x = 3(8) = 24
Singles = 45(x-3) = 45(8-3) = 45(5) = 225
<em>Answer,</em>
100,000,000 > 334,605,925
But, 100,000,000 is smaller that 334,605,952
So, It would be "100,000,000 < 334,605,925"
6/x= -2/18
Cross multiply. ( Multiply the numerators together ) . ( Multiply the denominators together (.
6*18= - 2*x
108= -2x
Divide by -2 for 108 and -2x
108/-2= -2x/2
x= -54
Answer: x= -54
9514 1404 393
Answer:
d. x-axis
Step-by-step explanation:
Consider a point on curve P and its (nearest) image on curve P'. The midpoint between those points is on the line of reflection. That line is the x-axis.
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<em>Additional comment</em>
The curve is symmetrical about the y-axis, so each point on P also has an image point that is its reflection across the origin. The reflection of P could be across both the x- and y-axes, or (equivalently) across the origin. We don't know the meaning of "xy-axis", so we suspect that is a red herring. The best choice here is "x-axis."
