Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
This is the answer, I can't write it with keyboard so here the pic
Remember pemdas
simpliify pathentsees, exponents then multiply divide add subtract
some exponential laws
we have
(-5m^2q)^2(-3m^3q)
do each seperately
(-5m^2q)^2=
[(-5)^2][(m^2)^2][(q)^2]=
[25][m^4][q^2]=
25m^4q^2
second part
(-3m^3q)^3=
[(-3)^3][(m^3)^3][(q)^3]=
[-27][m^9][q^3]=
-27m^9q^3
so we multiply them together
(25m^4q^2)(-27m^9q^3)=
(25)(m^4)(q^2)(-27)(m^9)(q^3)=
(25)(-27)(m^4)(m^9)(q^2)(q^3)=
(-675)(m^13)(q^5)=
-675m^13q^5
answer is first one
Answer:
the required answer is 3...
Answer:
4/5
Step-by-step explanation:
4/5 x 5/5 = 20/25 = 4/5