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scoundrel [369]
3 years ago
9

Please help me it’s very important

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

Step-by-step explanation:

The answer to ur question 80

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true or false: we want the leading coeffient of a polynomial to be a positive number whenever possible
EastWind [94]
That is false... coefficients in polynomials can lead in either positive or negative 
4 0
3 years ago
Read 2 more answers
Find four consecutive even integers whose sum is 84. Find the integers.
mina [271]
Suppose the integers are n , n+2 , n+4 and n+6.
84=n+(n+2)+(n+4)+(n+6)=4n+12.
Subtract 12 from both ends to get.
72=4n.
Divide both ends by 4 to get.
n=18.
So the integers are: 18 , 20 , 22 , 24.
4 0
3 years ago
Can someone plz help
irga5000 [103]

Answer: I think it would be 8!

Step-by-step explanation: I hope this help!

8 0
2 years ago
Read 2 more answers
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
58. 122. 61. None of the choices are correct
In-s [12.5K]

Answer:

C. 61

Step-by-step explanation:

Two sides are equal, so the triangle is an isosceles triangle.

Both base angles are equal.

Angles in a triangle add up to 180 degrees.

58 + x + x = 180

58 + 2x = 180

2x  = 122

x = 61

8 0
3 years ago
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