Answer: Rahul walks 2.7 km more than Vansh.
Step-by-step explanation:
The options include:
a. Vansh walks 7.2 km more than Rahul.
b. Vansh walks 2 km more than Rahul.
c. Rahul and Vansh both cover the same distance.
d. Rahul walks 2.7 km more than Vansh.
Distance covered by Rahul weekly = 9km
Distance covered by Vansh weekly = 900m × 7 = 6300m = 6300/1000 = 6.3km
From the above, we can see that Rahul walk (9km - 6.3km) = 2.7km more than Vansh.
Note: 1000 meters = 1 kilometers
Hello Friend,here is the solution for your question
<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)
Now here in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>
And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0 [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>
<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
=√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
=√1/8
=1/(2√2)
<span>this is the maximum value now to find the minimum value </span>
<span>since this is function of root so the value of y will always be ≥0 </span>
<span>hence the minimum value of the function y is 0 </span>
<span>Therefore, the range of function </span>y is [0,1/(2√2)]
__Well,I have explained explained each and every step,do tell me if you don't understand any step._
Answer:
33.333333333333%
Step-by-step explanation:
Answer: It should be an 8th grade level
(sorry if i'm wrong)
:(
(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.
