Answer:
(6x² - 5)(x² + 2)
Step-by-step explanation:
Given
6
- 5x² + 12x² - 10 ( factor the first/second and third/fourth terms )
= x²(6x² - 5) + 2(6x² - 5) ← factor out (6x² - 5) from each term
= (6x² - 5)(x² + 2)
Fter<span> a </span>125<span>% </span>markup<span> and a </span>10<span>% </span>discount<span> the </span>price<span> of a </span>watch<span> is 30.78 </span>before tax<span> what was the </span>wholesale price<span> - 2929721. ... If an item is $15.20 is increased by </span>125<span>% (34.20) it would be about $34.20 </span>before<span> we subtract </span>10<span>% (3.42)....we arrive at the end </span>cost<span> of </span>$30.78<span>. </span>wholesale price<span>would be 15.20.</span>
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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Answer: idk
Step-by-step explanation:
idk
Answer:
A≈1135.93
Step-by-step explanation:
Hope I help
